Help with some Math

(Q1.) There are more additive combinations

(Q2.) t=x+y when x and y are equal the sum of two integers ranging from 1 to 6, so you have 6 possible x's, and each x has six possible y's. You could look at this the other way since addition of integers commute (a+b=b+a)

(Q3.) (1)Roll Dice-a lot---10's of thousands of times (assuming they aren't loaded), (2)write a routine modeling the rolling of two dice and run it 10's of thousands of times, (3) Think about something else and go play roulette.

(Q4.) Think about the possible combinations (t=x+y) and plot the crunched data, say percentage for each hit a bar graph.

Rap

Re: Help with some Math

it's a fact, provided the dice aren't loaded.

Build a table
I think the best way to answer some of your questions is to build the table of all possible combinations. Since each die can produce a number between 1 and 6, there are 36 possible throws in your 6x6 table, each with the same likelyhood of occuring. Looking at this table...

Q1. It is obvious that is it easier to get some numbers than others just be reading down the diagonals. The number seven occurs in six of the combinations and is the maximum. 2 and 12 only occur once each.

Q2. Your table shows all the possible rolls. If you want to find the number of ways to get a total of six, just count them. The pattern will be obvious enough after a couple of tries.

Q3. There are 36 total combinations possible. If you want to know how many times you expect to get a seven, just count the number of blocks that add up to seven (6) and divide by the total (36). Looks like a 1 in 6 chance of getting a seven.

Q4. There are several ways of doing this and the easiest does not use the percentages calculated. Just all up all the values in the table and divide by the number of blocks.