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Geometrical: Depiction of trigonometric graphs

 
 
Red888
 
Reply Mon 9 May, 2005 11:25 am
Well here is one which threw me off track. Especially 6.4

Would anyone mind assisting me with this question please. I'd appreciate it.


http://www.kaitenkenbu.net/wraith/Math/Geometricalq6.jpg
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Type: Discussion • Score: 1 • Views: 554 • Replies: 5
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Vengoropatubus
 
  1  
Reply Mon 9 May, 2005 12:58 pm
f=2 sin x
I think g= cos x
and
h= -tan x
G's period is 360 degrees

You should be able to do 6.3

I'm not even sure what 6.4 is trying to say.
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Red888
 
  1  
Reply Wed 11 May, 2005 01:11 pm
Yeah. No clue about 6.4 I was hping you guys would know. Wierd question. Ta for help though.
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markr
 
  1  
Reply Wed 11 May, 2005 01:34 pm
g's period looks like 180 degrees to me.

6.4: The notation looks odd (comma and semicolon?). It looks to me like it's saying that f and g intersect at A and B. If the x-coordinate of A is 11.95, what is the the y-coordinate (k)? What are the x- and y-coordinates of B?
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Vengoropatubus
 
  1  
Reply Thu 12 May, 2005 08:34 pm
you're right about g's period, it is 180
0 Replies
 
satt fs
 
  1  
Reply Thu 12 May, 2005 08:53 pm
6.4)
k=2/sqrt(5)

(Take squares of both sides of 2sin(x)=cos(x) and use sin(x)sin(x)+cos(x)cos(x)=1.)
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