help

2sin2a - 1 = 0

2sin2a = 1

sin2a = 0.5

2a = arcsin 0.5

= 30 degrees or 150 degrees

a = 15 or 75 degrees

that's not what he's looking for, Beka.

sin(2a)=2(cos a sin a)
so,
4(cos a sin a)=1
cos a sin a= .25
I can't seem to recall how to solve this.

edit: actually, you are right. You're just short two solutions.

Ooops somehow i forgot the double angle identities!! And i call myself a math student I'm so blonde tonight