Simple Math Problem

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Ok, this is a very simple math problem, but for some reason I am completely forgetting how to do it. So I just wanted to ask this question for future reference to make sure I do know how to do this...

OK. Let's say there is a lottery, and for each of the six spots on the ticket, you need to pick a number 1-30. You must have a different number for each spot. How many possible combinations of numbers are there?

Thanks in advance for the simple help Very Happy

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30!/ 6*(30-6)! if I remember correctly...

hmmm, not sure about that 6, but it should be 30*29*28*27*26*25. I guess if order doesn't matter you need to divide by 6 to remove duplicates.

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Close Freeduck but you left out a factorial.

The odds of drawing a winner (in order is)

P(E)=6/30*5/29*4/28*3/27*2/26*1/25=1/593775

This is the same as

P(E)=1/{30!/[6!(30-24)!]}=(6*5*4*3*2*1)/(30*29*28*27*26*25)=1/593775

So the odds on winning is about 1 out of 600,000

Rap

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Ah, you are right. I certainly forgot that part of the formula.

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Simple Math Problem

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