Help, how to solve this question?

a(-8)-5 = 0
a(-8) = 5
a = 5/(-8)
a = -5/8

So, the denominator then becomes SQRT(-(5/8)x - 5).

If x is -9, this is SQRT(45/8 - 5) = SQRT(5 5/8 - 5) = SQRT(5/8)

If x is -8, this is SQRT(5 - 5) = 0

If x is -7, this is SQRT(35/8 -5) = SQRT(4 3/8 - 5) = SQRT(-5/8), which is not defined within real numbers.

since x<-8, then f(x) is undefined at x=-8, or a(-8)-5=0.

So a=-5/8 and as x-->-8, f(x)-->+infinity
and as x--> - infinity, f(x)--> 0.

So the range of this function for the given domain (- infinity to <-8) is 0 to +infinity.

Rap