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NeoPets Riddles (Lenny Conundrums) and Answers Here

 
 
shelby rox888
 
  1  
Reply Thu 16 Mar, 2006 08:30 am
Old Cap'n Bloodhook, the captain of The Black Pawkeet, needed to pack away some of his hoarded dubloons(refering to the actual circular object). "I'll tell you what," he said, "if ye can help me figure out how many dubloons(could refer to either the circular project, or the amount that the dubloon stands for) can fit into this tray, I'll be givin' ye a reward!"

So the tray is perfectly square, and just big enough to fit 10 dubloons(most likely the thing, could be the amount of dubloons) along one side.

So, without overlapping any dubloons(the circular object), what is the maximum number of dubloons(thing, or amount in the thing) that can fit in the tray?

Understand what I said? It could be mean what the dubloons amount to
eg. five dubloon coin= 5 one dubloon coins
0 Replies
 
shelby rox888
 
  1  
Reply Thu 16 Mar, 2006 08:39 am
Or of course, the amount of dubloons has nothing to do with it.

Which I would then go to markr's little picture thing... which I am now pretty sure is the correct answer Very Happy Off I got to submit... and hope for the best.
0 Replies
 
stapel
 
  1  
Reply Thu 16 Mar, 2006 09:46 am
shelby_rox888 wrote:
It could be mean what the dubloons amount to, eg. five dubloon coin= 5 one dubloon coins

This might be the case if all the coins are of the same size. But is this the case?

As was requested earlier, if you are wanting to consider differently-valued coins, please provide the sizes (dimensions) of those coins. Thank you.

Eliz.
0 Replies
 
pooh2ntigger2
 
  1  
Reply Thu 16 Mar, 2006 10:23 am
lenny today
based on looking at all the coins i have in my sdb they look to all be the same dimensions. using the screen pic they gave looks like 1 inch for each. But it takes 10 to fill along side. to be perfectly square thats 10x10 of coins. Is that a help to start this calculation?
0 Replies
 
pooh2ntigger2
 
  1  
Reply Thu 16 Mar, 2006 10:49 am
dont need any dimensions really this is easy. a perfect 10 coins along one side. to be perfect 10 x 10 = 100 coins
0 Replies
 
MindyH
 
  1  
Reply Thu 16 Mar, 2006 11:23 am
It wouldn't fit more because they are circles because the middle is still the same size. The missing edges wouldn't allow you to accomodate more circles if they are perfectly cut.
0 Replies
 
stapel
 
  1  
Reply Thu 16 Mar, 2006 11:24 am
pooh2ntigger2 wrote:
dont need any dimensions

If, as some have posited, we should consider coins other than only "the dubloon" coin (such as the five-dubloon coin), then, yes, we need to know the sizes of these other coins.

pooh2ntigger2 wrote:
really this is easy. a perfect 10 coins along one side. to be perfect 10 x 10 = 100 coins

Actually, as was ably demonstrated earlier, this is very clearly not the case. Sorry.

Eliz.
0 Replies
 
testify
 
  1  
Reply Thu 16 Mar, 2006 01:37 pm
After going over the problem myself and visiting the site markr provided, I agree with him.
It can't just be 10 x 10= 100.
I guessed 106, so hopefully we'll see next week!
0 Replies
 
etheon
 
  1  
Reply Thu 16 Mar, 2006 01:56 pm
i'm going with 106 Smile thank you all.
0 Replies
 
joe8390
 
  1  
Reply Thu 16 Mar, 2006 02:54 pm
LC Conundrum
Has anyone thought that the dubloons could be stacked upright? So you could have them like in a coin tray at a casino with ten columns of x number of coins dependent on the thickness. The only problem with this is that i don't know how to work out the thickness of the coin.

I'm new here btw

Joe
0 Replies
 
KJFJustice
 
  1  
Reply Thu 16 Mar, 2006 03:23 pm
Hi all.
Hello all. I decided to post my answer here b/c I've gotten help here from all of you before.

I went with total number of coins having nothing to do with value. The question is: how many can you fit into a square if you can fit 10 along one side? Well take out some pennies and make a square with 36 of them on a piece of paper. Then draw a sqaure around those pennies. Make sure it's right up to the edge of the pennies and there's no extra space. There's your square. Now fit as many pennies as you can into that square. You should find that you can fit more than 100 if you put them in a diagram similar to the stars on the United States Flag. That means from top to bottom you'll have 11 rows of coins in alternating amounts of 10 and 9 each, starting with 10 and ending with 10, for a total of 105 coins.

I initially blew it by rushing this effort. I made 12 rows and had six each of 10 and 9 coin rows for a total of 114. But I then realized I simply drew my square too big. Oh well.
KJFJustice
0 Replies
 
elybelly
 
  1  
Reply Thu 16 Mar, 2006 06:22 pm
New LC
The largest denomination coin is 1000. Actually the Platinum dubloon is even bigger (I believe) but Neopets doesn't say exactly how many dubloons a platinum dubloon equals. Does anyone know? I would assume the only way to know would be to spend one dubloon at the Golden Dubloon and count the change to see what it equals, but I'd think it was unnecessary. I think the question is really how many dubloons (the AMOUNTS) can fit in the tray. But as other people have pointed out, this is one of those questions that can go either way. It's purposely ambiguous to minimize the number of right answers. I multiplied 106 (the maximum amount of physical coins that fit) by 1000 (the highest value dubloon) and submitted an answer of 106,000 dubloons. Anyone with me? =)
0 Replies
 
bornawitch
 
  1  
Reply Thu 16 Mar, 2006 06:28 pm
MindyH wrote:
It wouldn't fit more because they are circles because the middle is still the same size. The missing edges wouldn't allow you to accomodate more circles if they are perfectly cut.

It might seem that way, but think about it. If you put 100 coins, in a gridlike manner, as you said, there will be a diamondlike space between 4 coins as so:
OO
OO
This is kinda hard to see, but in the very center of the group, there's that space in the middle. If you arrange the coins in a way similar to that of the stars on the american flag, the gaps in the middle will be significantly smaller. So much smaller, that you can fit an extra 6 coins in. Smile If you don't get what I mean, go to page 194 and look at markr's diagram. It is very clear. Thanks.

-Tams
0 Replies
 
the veronicas rule
 
  1  
Reply Fri 17 Mar, 2006 12:53 am
Yes but what if the dubloons were standing up on their side instead of being flat
Then dubllons would be rectangular, looking from the top, not round
so think about it that way
0 Replies
 
joe8390
 
  1  
Reply Fri 17 Mar, 2006 01:53 am
yeh i thought bout that. its just there's no way of calculating the thickness of the dubloons with just the radius which is 0.5.
0 Replies
 
the veronicas rule
 
  1  
Reply Fri 17 Mar, 2006 07:06 pm
tru, so does enyone have an answer that they are a 100% of?
Confused Sad Question Question Question Question
0 Replies
 
alexxander258
 
  1  
Reply Sat 18 Mar, 2006 07:44 pm
yes it's true mark's diagram rae very clever but i think that's not the answer

what if the circle not fit with the dubloon
0 Replies
 
spifftastic
 
  1  
Reply Sun 19 Mar, 2006 06:45 pm
Hello there. I'm new. I've been trying to crack the LC answers for a while now! Then I found this awesome site. Okay, I'm not completely sure, but as one of you said, like the stars on the american flag, they are spaced in a way to make spaces in between them Hoever, why can it be that some dubloons may be lying down so that the circular structure is showing, yet others are up. The only problem is the diameter of the side of the dubloon and the measured amout of space in between them all. Any ideas?
0 Replies
 
Jen Aside
 
  1  
Reply Mon 20 Mar, 2006 05:13 am
The value of the coins should be irrelevant, as should the thickness, since it's impossible to solve the problem without knowing those IF you need to know those.

Value:
Suppose the problem was, "How many dubloons can you fit into a box that fits exactly one dubloon?" You can't say, "Whatever the value of the largest denomination of dubloon is," because you are then changing the definition of what a "dubloon" is in the middle of the problem. Therefore, the problem [ideally] is referring to physical coins, not value.

Tipping sideways/stacking coins:
That we are given neither the thickness of the coins nor the height of the box makes it impossible to determine how many could fit in this fashion without guessing, and since we are looking for a definite answer, these must be irrelevant.

I propose markr's solution to still be the correct one.
0 Replies
 
the veronicas rule
 
  1  
Reply Wed 22 Mar, 2006 04:34 am
This is strange
Can I just say, that theres a place in the neopian bazaar & if you click on the NP that appears in different places, sometimes youll get the 200NP & sometimes you wont!! its at Neopets: Coming Soon!! Crying or Very sad
0 Replies
 
 

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