605
   

NeoPets Riddles (Lenny Conundrums) and Answers Here

 
 
Joanneexoxo
 
  1  
Reply Tue 7 Dec, 2010 09:52 pm
@wertyiu102,
What's the answer? tell me pls.
0 Replies
 
wertyiu102
 
  1  
Reply Wed 8 Dec, 2010 12:36 pm
Okay, I'm telling. No-wait. It sent me a neomail, but you can still answer? Okay, not telling yet. Buahaha
0 Replies
 
wertyiu102
 
  1  
Reply Wed 8 Dec, 2010 01:05 pm
This weeks solution: [sorry Lennyfan]

This LC mentioned the Advent Calendar. So you go there, and you see this button on the bottom. Click it, and it leads you to the archives. You start on Year 2, day 1. If you click the next day, you see a Snow faerie. If you increase the year by one, and increase the day by one, you'll get a Jub Jub. Keep doing this, and one after the Skeith and the Eyrie is a Kougra and a Mynci around a Christmas tree.

Answer: Kougra and Mynci
0 Replies
 
ro67
 
  1  
Reply Wed 8 Dec, 2010 04:42 pm
I got 7 digits, sum of 30
vvktv
 
  1  
Reply Wed 8 Dec, 2010 04:56 pm
@ro67,
mine was sum of 29 but i rounded down...
sevoweeks
 
  1  
Reply Wed 8 Dec, 2010 04:57 pm
@ro67,
So did I. I was worried because it seemed too large, but seeing someone else get the same answer consoles me a little :p
0 Replies
 
lennyfan
 
  1  
Reply Wed 8 Dec, 2010 05:20 pm
Since no one has put the actual puzzle out there yet:

The current prize for the first 250 correct entries is a Winter in Faerieland.

THIS WEEKS PUZZLE:

Faerieland is a wonderful world that rests on magical clouds that float over Neopia. (Well, at least, they used to float over Neopia...)

These clouds are made of a special magical lightweight polymer material that supports the weight of the world on top of it. The clouds weigh 63.4 kilograms per cubic metre. And the cloud is a massive hemisphere, 3450 metres in diameter. Also, assume all of the buildings, faeries, and other objects on top of the cloud weigh 750,000 kg.

If one faerie's magic can cause 123,456 kg of weight to float in the sky, how many faeries are required to keep all of Faerieland floating? Disregard any buoyancy effect from the surrounding air, and be sure to round up to the nearest whole number.
0 Replies
 
lennyfan
 
  1  
Reply Wed 8 Dec, 2010 05:21 pm
I agree with the 7 digits, sum of 30. Relatively simple, although I did take the time to find a big number calculator on the web and make sure I wasn't getting any round off errors. Probably the key thing to note is that the cloud is a hemisphere and not a full sphere.
0 Replies
 
skutn1em
 
  1  
Reply Wed 8 Dec, 2010 05:49 pm
@vvktv,
It says specifically in the puzzle to round up to the nearest whole number. Agree with 7 digits, sum of 30.
0 Replies
 
wertyiu102
 
  1  
Reply Wed 8 Dec, 2010 07:39 pm
Agreed. Very Happy 7 digits, sum of thirty. round up!
0 Replies
 
mydisguise08
 
  1  
Reply Wed 15 Dec, 2010 01:01 pm
Round: 381

Faerieland is a wonderful world that rests on magical clouds that float over Neopia. (Well, at least, they used to float over Neopia...)

These clouds are made of a special magical lightweight polymer material that supports the weight of the world on top of it. The clouds weigh 63.4 kilograms per cubic metre. And the cloud is a massive hemisphere, 3450 metres in diameter. Also, assume all of the buildings, faeries, and other objects on top of the cloud weigh 750,000 kg.

If one faerie's magic can cause 123,456 kg of weight to float in the sky, how many faeries are required to keep all of Faerieland floating? Disregard any buoyancy effect from the surrounding air, and be sure to round up to the nearest whole number.



Answer: 5520819
0 Replies
 
lennyfan
 
  1  
Reply Wed 15 Dec, 2010 04:08 pm
Volume of a sphere = (4/3) pi * r^3. Half of that for a hemisphere.

r = 3450 /2 = 1725 m. Volume = 1.0750432 x 10^10 m^3

Mass = density * volume (plus the extra volume of stuff on top of the clouds)
Mass = 63.4 * 1.0750432 x 10^10 + 750000 = 6.8157813 x 10^11 kg

# of faeries = mass / (mass per faerie) = 6.8157813 x 10^11 / 123456 = 5520818.2, which rounds up to 5520819. Turns out that a normal calculator is sufficient to preserve enough significant digits, although I did do a double check to make sure, using a big-number (1000-digit) calculator.
0 Replies
 
lennyfan
 
  1  
Reply Wed 15 Dec, 2010 04:31 pm
New one is up - Christmas tree with a bunch of letters hanging on it as ornaments.

What Neopian word, phrase, or name can be found or inferred from this image? Enter ONLY the answer with no extra words or punctuation, or your answer will be marked wrong!

This week's prize is a Christmas Tree Shampoo.
0 Replies
 
beebzzz
 
  1  
Reply Wed 15 Dec, 2010 04:32 pm
the letter in the bottom, is it a C or a G?
0 Replies
 
komo95
 
  1  
Reply Wed 15 Dec, 2010 04:35 pm
It's a C ^^
beebzzz
 
  1  
Reply Wed 15 Dec, 2010 04:40 pm
@komo95,
got it, thanks Smile
komo95
 
  1  
Reply Wed 15 Dec, 2010 04:48 pm
@beebzzz,
No problem! =)

With this one I think I may finally be on the highscore table, lol xD
0 Replies
 
eilonwy42
 
  1  
Reply Wed 15 Dec, 2010 04:52 pm
No high score for me. Is this an anagram, or am I barking up the wrong tree?
lennyfan
 
  1  
Reply Wed 15 Dec, 2010 04:56 pm
@eilonwy42,
I'd say barking up the right tree.
eilonwy42
 
  1  
Reply Wed 15 Dec, 2010 05:02 pm
@lennyfan,
crap...horrible at anagrams!
 

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