w00t Gibb0n
Hmm hey i think i found the answer.
Cerrect me if i go wrong somewhere....
I used excel to work it out so there's no real easy way to explain.
I made a list of numbers from 100 down to 1 in the first column to represent the number of bricks along one side of the pyramid on each layer.
Then i made the next column the previous numbers multiplied by four to represent the number of brick side faces that require paint from each layer of the pyramid.
Then i found the sum of all of the numbers from the second column to represent the total number of side faces (97*63 in size) that were to be painted.
The sum being 20200 faces was then multipied by the surface area in cm
20200*97*63 = 123442200 cm squared
I then made a third column which was the numbers in column 2 minus 4 from each to account for the fact that there is only one top face (97*97 in size) in each corner instead of 2 side faces (1 surface less from each corner and there's 4 corners). Then divided by two because each layer covers half of the surface area of the top faces of the layer below it. With the exception of the top layer being one full top surface.
The sum of these is the total number of top faces requiring paint.
The sum being 9901 surfaces was then multiplied by the surface area in cm
9901*97*97 = 93158509 cm squared
Now knowing these 2 figures we could add them together to find the total surface area needed to be covered by the paint.
123442200 + 93158509 = 216600709cm squared
Then divide this figure by 100 to find the total surface area in meters squared.
216600709/100 = 2166007.09m squared
Then this figure divided by 3 would give us the total number of liters of paint required to paint the surface of the pyramid.
2166007.09/3 = 722002.36 liters
rounded up because it says to do so =
722003 Liters
Here's the Excel File
---> Here <---