if the circumference of the full circle is 4398.2cm then each of the arcs are 199.5cm. Then each one is in three equal parts I guess so the shaded area has four equal sides of 366.52cm but I'm not sure how to get the surface of that odd shape.
I think you're on to something, dexsgrl. But I don't understand the last diagram at the link. That is, I can calculate 1/12 x the area of the circle. But how do I find the height and base of the triangles whose area I need to subtract?
And by my calculations...PIxRxR=96211.5 cm as the area of a quarter circle. Did anyone else get that?
R = 700, so R*R = 490000. I think you are on the low side.
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edstock
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Wed 11 Feb, 2009 06:13 pm
Area of quarter circle should be .25 * PI * R * R, where R = 700. Then if we take the area of the square (700 * 700) and subtract, we can get the area outside of the quarter circle.