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NeoPets Riddles (Lenny Conundrums) and Answers Here

 
 
Tiamka
 
  1  
Reply Wed 30 Apr, 2008 08:31 pm
my length in five digits long, but I do tend to mix up my exponents. So I might be off by an order of magnitude or two...or three.
0 Replies
 
princessfroggy
 
  1  
Reply Wed 30 Apr, 2008 08:33 pm
I think I might have found my mistake. My answer it 3 digits and adds up to 15 Very Happy ... I am going to figure it up on more time just to be sure.
0 Replies
 
catfood
 
  1  
Reply Wed 30 Apr, 2008 08:35 pm
im gonna give another hint to my answer but hopefully you don't post it here. yeah, my digits add up to 15 too.
0 Replies
 
princessfroggy
 
  1  
Reply Wed 30 Apr, 2008 08:38 pm
catfood wrote:
im gonna give another hint to my answer but hopefully you don't post it here. yeah, my digits add up to 15 too.



Yay! Very Happy I hope I am right then, though there are a several numbers between 100 and 199 that add up to 15 Rolling Eyes Oh well, I'm happy I even got close.
0 Replies
 
ThezeR2HarD
 
  1  
Reply Wed 30 Apr, 2008 08:40 pm
i have a question
what do you do to the answers u get from the equations?
V1 = 4/3 * pi * (r1)^3
V2 = 4/3 * pi * (r2)^3
0 Replies
 
catfood
 
  1  
Reply Wed 30 Apr, 2008 08:43 pm
ThezeR2HarD wrote:
i have a question
what do you do to the answers u get from the equations?
V1 = 4/3 * pi * (r1)^3
V2 = 4/3 * pi * (r2)^3


We use that to put into the last equation:

h/3* V2 + A*h = m/d - V1
0 Replies
 
ThezeR2HarD
 
  1  
Reply Wed 30 Apr, 2008 08:45 pm
catfood wrote:
ThezeR2HarD wrote:
i have a question
what do you do to the answers u get from the equations?
V1 = 4/3 * pi * (r1)^3
V2 = 4/3 * pi * (r2)^3


We use that to put into the last equation:

h/3* V2 + A*h = m/d - V1

ok thanks but my problem is that i dont known how to do the rest of the problem Confused
0 Replies
 
ThezeR2HarD
 
  1  
Reply Wed 30 Apr, 2008 08:51 pm
wait when you divide mass by density, do u use 7800 as the density?
0 Replies
 
cosmic axe
 
  1  
Reply Wed 30 Apr, 2008 08:52 pm
This is a puzzle solving site and not a Neopets site so all puzzles can be solved here and the answers posted without having to give silly hints and stuff Very Happy Perhaps there is a Neopets forum where you can do that sort of thing?
0 Replies
 
catfood
 
  1  
Reply Wed 30 Apr, 2008 08:59 pm
yeah, the unit is in kg and meter so we have to use 7800
0 Replies
 
likesachallenge
 
  1  
Reply Wed 30 Apr, 2008 09:01 pm
can anyone confirm this?

rho = F /A

rho = 400,000,000 kg/m*s^2

rho is stress, F = force, A = cross area of bar

A = 5/4*t^2*tan(54) (54 is degrees)

t = 0.02 m

F = rho * 5/4*t^2*tan(54)

F = m*g

m = F /g

g = 9.81 obviously

m = (mass of big sphere) + (mass of little spheres) + (mass of bar)

mass of little spheres = l/3*(mass of 1 little sphere, which is volume of little sphere * d) (l = length of bar rounded down)
mass of bar = A*l*d (d = density which is 7800 kg/m^3)
mass of big sphere = d*(volume of big sphere)

volume of big sphere = 4/3 * pi * (.25m)^3 (the .25m is the radius of the big sphere)
volume of bar = 4/3 * pi * (.15m)^3

if we multiply out by the densities we get

(volume of big sphere) + (l/3)*(volume of little sphere) + A*l = m/d
(l/3)*(volume of little sphere) + A*l = m/d - (volume of big sphere)

now we solve for l (the length it can be)

l = (m/d - (volume of the big sphere))/((volume of little sphere)/3 + A)

(volume of big sphere) = 0.0654497917
(volume of little sphere) = 0.014137155

F = rho * A
F = 275276.384
m=F/g
m =

l = (28060.7935/7800 - (0.0654497917)) / (0.014137155/3 + 0.00068819096)
0 Replies
 
walsh028
 
  1  
Reply Wed 30 Apr, 2008 09:01 pm
i found this from somewhere else..to get rid of those silly hints that makes the world harder to live in...

rho = F /A

rho = 400,000,000 kg/m*s^2

rho is stress, F = force, A = cross area of bar

A = 5/4*t^2*tan(54) (54 is degrees)

t = 0.02 m

F = rho * 5/4*t^2*tan(54)

F = m*g

m = F /g

g = 9.81 obviously

m = (mass of big sphere) + (mass of little spheres) + (mass of bar)

mass of little spheres = l/3*(mass of 1 little sphere, which is volume of little sphere * d) (l = length of bar rounded down)
mass of bar = A*l*d (d = density which is 7800 kg/m^3)
mass of big sphere = d*(volume of big sphere)

volume of big sphere = 4/3 * pi * (.25m)^3 (the .25m is the radius of the big sphere)
volume of bar = 4/3 * pi * (.15m)^3

if we multiply out by the densities we get

(volume of big sphere) + (l/3)*(volume of little sphere) + A*l = m/d
(l/3)*(volume of little sphere) + A*l = m/d - (volume of big sphere)

now we solve for l (the length it can be)

l = (m/d - (volume of the big sphere))/((volume of little sphere)/3 + A)

(volume of big sphere) = 0.0654497917
(volume of little sphere) = 0.014137155

F = rho * A
F = 275276.384
m=F/g
m =

l = (28060.7935/7800 - (0.0654497917)) / (0.014137155/3 + 0.00068819096)
l = 654.020583


Then you round l and plug it into the previous forumla

l/3* (volume of the small sphere) + A*l = m/d - (volume of the big sphere)
l/3 * 0.014137155 + 0.00068819096 * l = 28060.7935/7800 - 0.0654497917
l/3 * 0.014137155 + 0.00068819096 * l = 3.53208784


If the left < the right add 1 to l, if it's >, take away one from l, the largest l you get without going over is the answer

(but you don't have to go any higher then 654 which you got for l)


i went with this answer and put 654
0 Replies
 
ThezeR2HarD
 
  1  
Reply Wed 30 Apr, 2008 09:01 pm
ok i get how to do the whole thing but i use a calculator to calculate and it gives me a number like 6.881.......e-4 as A. what would A be in numeral form?
0 Replies
 
roxiegirl
 
  1  
Reply Wed 30 Apr, 2008 09:03 pm
princess, it is between 100 and 999
0 Replies
 
roxiegirl
 
  1  
Reply Wed 30 Apr, 2008 09:04 pm
654? thats not what i got.
0 Replies
 
roxiegirl
 
  1  
Reply Wed 30 Apr, 2008 09:04 pm
catfood?
0 Replies
 
walsh028
 
  1  
Reply Wed 30 Apr, 2008 09:04 pm
thats your answer..but thats not what the others solved..im just trying to help and not make the confusion a rat runaround thank you
0 Replies
 
princessfroggy
 
  1  
Reply Wed 30 Apr, 2008 09:05 pm
roxiegirl wrote:
princess, it is between 100 and 999


I know, thats what I meant.
0 Replies
 
roxiegirl
 
  1  
Reply Wed 30 Apr, 2008 09:06 pm
walsh, to clarify, people on this board do like to make other people work a LITTLE bit before posting the answer.
0 Replies
 
walsh028
 
  1  
Reply Wed 30 Apr, 2008 09:06 pm
really..ok
0 Replies
 
 

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