NeoPets Riddles (Lenny Conundrums) and Answers Here

So is 4617 the answer??

Sorry i meant 4716,is it the correct answer?

I have the silver now, but I did get the bronze first. I've been lucky enough to get into the top 250 3 or 4 times. But they are usually ones I'm able to figure out on my own. Although I use this board every week since I found it, even if I don't post. If I don't think I can help I just keep reading all the posts.

Yes, it counts how many times you have been in the first 250, since that's always how it scored them. The "all correct answers get a prize" thing is a more recent addition to TRY to prevent people from sharing the answer, but it's clearly not a perfect solution =/

I know what you mean. I'm kinda the same way. I lurk sometimes too so I can get ideas or (I'll admit it) answers because I'm stumped.

this one's so confusing, so i just entered 4716 i hope it's right

Congrats Yuma





an interesting thing I found when I started was:
9753 -
3579
6174

or

8642 -
2468
6174

Both when reversed give 4716 which led me to those digits to try out (and Yuma's answer confirmed - so thanks again Yuma!)

What time?
What time does the new one usually get posted each week? does it vary by hours... or min?

How to find the answer to round 228
Yuma07, I'm curious as to how you came up with the answer. I used the brute force method of trying every 4 digit number, checking for uniqueness of the digits, finding the largest and smallest reorderings, taking the difference and comparing it to see if it is the reverse of the initial number.

Of course, I'm a programmer, so my web page did it for me. VBScript code for anyone interested (sorry about the lack of indentation - the editor keeps it, but the display doesn't show spaces or tabs and doesn't like the non-breaking space character):

dim a, b, c, d, n(4)
for a = 0 to 9
for b = 0 to 9
for c = 0 to 9
for d = 0 to 9
n(0) = a
n(1) = b
n(2) = c
n(3) = d
if SortUniqueArray(n) then
diff = 999 * (n(0) - n(3)) + 90 * (n(1) - n(2))
n(3) = diff mod 10
n(2) = (diff \ 10) mod 10
n(1) = (diff \ 100) mod 10
n(0) = (diff \ 1000) mod 10
if n(0) = d and n(1) = c and n(2) = b and n(3) = a then
Response.Write CStr(a) & CStr(b) & CStr(c) & CStr(d) & ": "
Response.Write "Found it!<br>"
end if
end if
next
next
next
next

function SortUniqueArray(byref n)
dim i, j, t

for i = lbound(n) to ubound(n) - 1
for j = i + 1 to ubound(n)
if n(i) = n(j) then
SortUniqueArray = false
exit function
end if
if n(i) < n(j) then
t = n(i)
n(i) = n(j)
n(j) = t
end if
next
next
SortUniqueArray = true
end function

question
I was wondering what the average amount of the 2,000,000np prize that the winning people get. Does that make sense?

Totally depends on the number of right answers. I have gotten only a couple hundred np upwards to about 1500-2000. The harder the question, the longer the first 250 can go, as fewer people guess or get it right.

Re: question


If you seriously mean the average across the different weeks, you can probably figure it out by going back through this topic and looking at the posts people have made reporting their winnings. Find as many different competitions as you can and take the average amount.

Re: question


It would actually be easier to get it straight from the Neopets site. They post the answer, how many people got it right, and how many NP they each won on the new features page. You can check archived news pages by clicking on 'Older news' right under the black bar that says Latest News.

So far in 2007, out of 33 weeks, there have been 31 LC awards posted, 2 weeks with nothing (around the time of the big site upgrade), and 1 week with a 'continued to next week' notice. If you got every answer right all year long, you would have accumulated a total of 44778 NP, for an average of 1444.45 NP per LC. Of course this is misleading, since almost half of that total was awarded in a single week, when only 95 people got the LC right. (2/7/2007 award was 21053 NP). If you pull that one from the mix, you get a more realistic average of 790.83.

I just wish I'd been on the ball the first week of February. :wink:

I need help
The archivist misplaced his shopping list inside one of the books. He has a handy way to remember which volume he placed it in, though. The volume number was a four-digit number, in which all four digits were unique. If you take the largest possible four-digit number that can be made by rearranging the four digits, and you subtract from that the smallest possible four-digit number that can be made by rearranging the four digits, the number you get is volume number, but with the digits in reverse order.

In what volume of the Encyclopedia Altadoria did he leave his shopping list?
Think u could help me on it

Think u know the answer 2 this 1 i cant get it
The archivist misplaced his shopping list inside one of the books. He has a handy way to remember which volume he placed it in, though. The volume number was a four-digit number, in which all four digits were unique. If you take the largest possible four-digit number that can be made by rearranging the four digits, and you subtract from that the smallest possible four-digit number that can be made by rearranging the four digits, the number you get is volume number, but with the digits in reverse order.

In what volume of the Encyclopedia Altadoria did he leave his shopping list?
Think u can help me plz

What objection do you have to the solution that was posted last week?

Or are you another Neopian whose browser is broken, so you can't see (or at least follow) the "Previous" link at the top of the page...?

Eliz.

Lenny Conundrum--shopping list
The Altadorian Archives are the repository of all Altadorian knowledge, science, and history. Thousands of books and scrolls populate its shelves. Amongst these books is the huge, multi-volume Encyclopedia Altadoria, volumes 1 through 9950. The archivist misplaced his shopping list inside one of the books. He has a handy way to remember which volume he placed it in, though. The volume number was a four-digit number, in which all four digits were unique. If you take the largest possible four-digit number that can be made by rearranging the four digits, and you subtract from that the smallest possible four-digit number that can be made by rearranging the four digits, the number you get is volume number, but with the digits in reverse order.
In what volume of the Encyclopedia Altadoria did he leave his shopping list?

I'm very confused on this one. When it says "If you take the largest possible four-digit number that can be made by rearranging the four digits", do they mean the four digits in the resulting number? That's what I'd expect.

Well, you know one thing: it has to be a number from 1023 to 9876. I'm currently making a chart that lists all possibe numbers, and then those numbers and others that have its digits in a different order. ll I know is, however many numbers there are, the answer could be out of (amount of numbers possible times 14.4 here). (Only because, in a 4-digit number, there are sixteen possibilities of ways the digits can be rearranged. Unless there's a zero, which would account for 10%of possible digits, thus could only account for 10% anyway. 16-(10%*16)=14.4. I think. I may have my math wrong there. *sigh*)

That's all I've been able to figure out. I think now I'm just going to try out random numbers...
Does anybody have any other ideas?

Lenny
Cool! Because of the help of this forum, I received a trophy!


Congratulations! You have guessed correctly in the Lenny Conundrum game (round 228). You have won 639 NP!

Because you were in the first 250 to guess correctly, you also have been awarded a Encyclopedia Neopia, and receive a trophy and the Lenny Conundrum avatar!

Yours Sincerely,
The Neopets Team!

Lenny
Thanx everyone!! Hope everyone did well too.

Dear Richard Carbajal,

Congratulations! You have guessed correctly in the Lenny Conundrum game (round 228). You have won 639 NP!

Because you were in the first 250 to guess correctly, you also have been awarded a Encyclopedia Neopia, and receive a trophy and the Lenny Conundrum avatar!

Yours Sincerely,
The Neopets Team!