New Neopia
WOW !!
Wonder if that is why there is no Lenny yet....
I don't know about anyone else but I like the new Neopets Layout. Now we must pay attention and await the new Lenny and hope it's an easy one and not a mind teasers.
new lenny
One day the regular transcriber was away, so a slightly hard-of-hearing substitute took his place. Unfortunately, he didn't do a very good job. In fact, he got almost every word wrong, instead replacing the words with other words that, more or less, rhymed with the actual words.
Anyway, King Skarl was reading aloud from the Neopedia, and the transcriber wrote it down as this:
"cry oppose fares bay curtain arm you berating snore gone pith homes bland elastic pennies..."
is this last weeks, they didn't post a new one in the news, but I got this when I went to games
debezzzz wrote:is this last weeks
Yes. That's why
a clue and
the solution were posted a week ago.
I guess the "Previous" links at the top and the bottom of the page aren't working for you...?
Eliz.
hi
Neopia is a strange little planet. Its gravitational acceleration at its surface is exactly 10.0 metres per second per second, and its diameter is exactly 2100 kilometres.
Also, a completely unrelated fact, Skeiths are able to consume about 0.4 kg of pretty much anything they want to eat, every minute, nonstop.
Assuming that the density of the planet is uniform, and that orbiting bodies don't significantly affect the planet's gravity, how many years will it take one million Skeiths to consume one cubic kilometre of Neopia? Please round up to the nearest year
g =GM/R^2 = (4pi/3) R^3 * d G /R^2 >>>
d = density of planet
g = (4pi/3) R* d G
------------------------------...
d = 3 g / 4pi R*G
d = 3*10 / 4*3.14*2100*10^3*6.67*10^-11
d = 1.705 * 10^4 kg/m^3
------------------------------...
Period of planet =
T = 2pi*sqrt[R/g] = 2878 sec = 47.967 min
------------------------------...
they eat up at rate
m-dot = 0.4 kg/minute/skeith
1 million will eat = 0.4*10^6 kg/min
1 million will eat = m-dot /d
= 0.4*10^6 /1.705 *10^4 = 23.46 (m^3/minute)
consumption rate = 23.46 m^3/minute
1 km^3 will be eaten in = (1000)^3 / 23.46 minutes
= 42625745.95 minutes
------------------------------...
actually, now the day of this planet shoulde be calulated first if the answer is to be given in days. if in years, its period of revolution around the controlling star should be known
------------------------------...
its dicey after this. I can calculate T (rotation) but you want T (revolution) ???
Wow Anneska!
That's some calculating.
got it from yahoo answers but it does not give any answer or help me in any why!
lenny
I don't think the size of it matters.
The question is how many years will it take one million skeiths to consume one cubic kilometre? And they consume .4 kg a minute.
I don't think the first sentence matters to the answer.
But that's just my thought right now!
well I can't remember a thing about science... so I am lost!
My sister gave me a data sheet with formulas but none seem to work for this problem!
The size would matter, because that's the only way you can calculate how long a day, and thus a year, is in terms of Neopia.
anneska, that's some impressive calculating! I was stuck after I worked out the mass of Neopia, which you had already put up!
sorry
sorry i didn't saw the answer
new Lenny Conundrum
Neopia is a strange little planet. Its gravitational acceleration at its surface is exactly 10.0 metres per second per second, and its diameter is exactly 2100 kilometres.
Also, a completely unrelated fact, Skeiths are able to consume about 0.4 kg of pretty much anything they want to eat, every minute, nonstop.
Assuming that the density of the planet is uniform, and that orbiting bodies don't significantly affect the planet's gravity, how many years will it take one million Skeiths to consume one cubic kilometre of Neopia? Please round up to the nearest year.
look at the previous page to see how far anyone has gotten.
devil, you gotta start looking at previous pages before you post something
ok
ok, sorry but i don't know very well how to work in this site
lenny
Does this make any sense or help at all.
If the diameter is 2100 kilometers then the circumference is x pi (3.14)
So 2100 x 3.14 = 6594 kilometers circumference.
6594 kilometers to meters is x 1000 so that equals 6594000 meters around neopia.
6594000 meters divided by 10 meters per second = 659400 seconds.
And 659400 seconds divided by 60 seconds in a minutes = 10990 minutes for neopia to rotate one time.
Does this help?
i see what you're saying, evil, but i'm pretty sure that gravitational acceleration at the surface means how fast an object falls to the surface due to gravity (i.e on Earth I believe it's 9.8 if my memory of distant physics courses is correct).
anneska used it to determine the density of the planet to calculate exactly how much mass is in a square kilometer.
