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a maths puzzle...

 
 
Reply Thu 30 Dec, 2004 04:16 pm
A person traveled from Meridell to Brightvale, 50 miles away, with his pet parrot. When he arrived in Brightvale, he let the parrot fly free while he traveled back to Meridell, at a speed of 10 miles per hour. The parrot, who flies at 25 miles per hour, arrived at Meridell and promptly turned around until he got to the person. Once he got to the person, he turned around and returned to Meridell. He continued to fly back and forth between the person and Meridell until the parrot reached Meridell.


How many miles total did the parrot travel on this trip?


i got this from neopets, i changed some words to make it less confusing.

could you also expain how to do it, if you can work out how to do it, i got stuck near the end.
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Type: Discussion • Score: 1 • Views: 1,458 • Replies: 14
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DrewDad
 
  1  
Reply Thu 30 Dec, 2004 04:23 pm
They key is total travel time.

The person walks 50 miles @ 10 miles/hour. That is 5 hours.

The bird flies 25 mph for 5 hours = 125 miles.
0 Replies
 
Caesar
 
  1  
Reply Thu 30 Dec, 2004 04:23 pm
im trying to figure out the EXACT same thingy buddy (see *Confused*)
0 Replies
 
Francis
 
  1  
Reply Thu 30 Dec, 2004 04:28 pm
but you must add the 50 miles the bird travalled with the person.
0 Replies
 
DrewDad
 
  1  
Reply Thu 30 Dec, 2004 04:32 pm
Ah, yes. Thank you, grasshopper.
0 Replies
 
omgwtflol
 
  1  
Reply Thu 30 Dec, 2004 08:32 pm
WRONG
it's funny cause you'll all wrong. it says that the bird flies BETWEEN the PERSON and the CITY. THE POSITION OF THE PERSON CHANGES EVERY HOUR, THEREFORE... the distance that the bird flies is NOT always 25 miles per hour... this makes ALL of your answers on all the posts of this wrong Sad for u guys. The only thing im debating about is the fact of using miles in decimals. You would use decimals because once the bird is on it's first way back to the person, the bird would be moving faster, making the person not walk the full 10 miles before the bird heads back.
0 Replies
 
Pantalones
 
  1  
Reply Thu 30 Dec, 2004 09:17 pm
Re: WRONG
drewdad got it when he got corrected.

omgwtflol wrote:
the distance that the bird flies is NOT always 25 miles per hour...


remember that distance is not velocity.
0 Replies
 
DrewDad
 
  1  
Reply Thu 30 Dec, 2004 10:42 pm
Re: WRONG
omgwtflol wrote:
it's funny cause you'll all wrong. it says that the bird flies BETWEEN the PERSON and the CITY. THE POSITION OF THE PERSON CHANGES EVERY HOUR, THEREFORE... the distance that the bird flies is NOT always 25 miles per hour... this makes ALL of your answers on all the posts of this wrong Sad for u guys. The only thing im debating about is the fact of using miles in decimals. You would use decimals because once the bird is on it's first way back to the person, the bird would be moving faster, making the person not walk the full 10 miles before the bird heads back.


Riddles of this type are quite common. I'm certain of my answer. If you dispute it, can you offer an alternate answer? With explanation?
0 Replies
 
markr
 
  1  
Reply Thu 30 Dec, 2004 11:10 pm
Re: WRONG
omgwtflol wrote:
it's funny cause you'll all wrong. it says that the bird flies BETWEEN the PERSON and the CITY. THE POSITION OF THE PERSON CHANGES EVERY HOUR, THEREFORE... the distance that the bird flies is NOT always 25 miles per hour... this makes ALL of your answers on all the posts of this wrong Sad for u guys. The only thing im debating about is the fact of using miles in decimals. You would use decimals because once the bird is on it's first way back to the person, the bird would be moving faster, making the person not walk the full 10 miles before the bird heads back.
The fact that the bird flies between the person and the city has been accounted for. Nobody said each leg of the bird's flight is a constant distance. However, the bird's speed is constant. Given that the bird flies for 5 hours at 25 mph, it must fly 125 miles. If you wish to calculate the length of each leg (using decimals), go ahead. However, it's not necessary, and if you do it correctly, you'll arrive at the same answer.
0 Replies
 
markr
 
  1  
Reply Fri 31 Dec, 2004 12:00 am
Oh, what the hell. Here are the distances traveled for each round trip the bird makes. Although this series is infinite, after 23 terms it converges to the answer to six decimal places. The first round trip is 71 3/7 miles. Each trip is 3/7 the length of the previous trip. Therefore, the total distance the bird flies is 71 3/7 * SUM(n=0 to infinity, (3/7)^n). The infinite sum is a geometric series that sums to 7/4 (sum = 1/(1-r), r = 3/7). 71 3/7 * 7/4 = 125.
Code:Remaining Distance Man Distance Bird
Distance Walks Before Flies From Man
For Man Bird Returns To City To Man
--------- ------------ --------------
50.000000 28.571429 71.428571
21.428571 12.244898 30.612245
9.183673 5.247813 13.119534
3.935860 2.249063 5.622657
1.686797 0.963884 2.409710
0.722913 0.413093 1.032733
0.309820 0.177040 0.442600
0.132780 0.075874 0.189686
0.056906 0.032518 0.081294
0.024388 0.013936 0.034840
0.010452 0.005973 0.014932
0.004479 0.002560 0.006399
0.001920 0.001097 0.002743
0.000823 0.000470 0.001175
0.000353 0.000201 0.000504
0.000151 0.000086 0.000216
0.000065 0.000037 0.000093
0.000028 0.000016 0.000040
0.000012 0.000007 0.000017
0.000005 0.000003 0.000007
0.000002 0.000001 0.000003
0.000001 0.000001 0.000001
0.000000 0.000000 0.000001
--------- ----------
Total 50.000000 125.000000
0 Replies
 
DrewDad
 
  1  
Reply Fri 31 Dec, 2004 01:29 am
You should have made him work it out himself....
0 Replies
 
markr
 
  1  
Reply Fri 31 Dec, 2004 02:43 am
You're probably right. Although, based on his post, I'm not sure he could have.
0 Replies
 
link oh ki
 
  1  
Reply Fri 31 Dec, 2004 12:44 pm
thanks everyone
0 Replies
 
iluvgiraffes
 
  1  
Reply Sun 2 Jan, 2005 09:05 am
more
wouldn't you have to add 50 to that because of the first trip?
0 Replies
 
markr
 
  1  
Reply Sun 2 Jan, 2005 11:40 am
Yes
0 Replies
 
 

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