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Thu 11 Nov, 2004 02:30 pm
A man walks 30 feet, turns right and walks another 30 feet. He then turns left and walks 10 feet. How far is the man from where he started?
Do I have to solve for two hypoteneus? How do I know the lenght of the legs of the second. I have come up with an answer of 50.2 feet but would like confirmation.
Please explain how you solved.
Thank you
Think of it as solving for the hypotenuse of a right triangle whose sides are 30 feet and 40 feet. He walked 30+10 feet in one direction and 30 in the other direction.
Thanks George. Doing it this way the numbers come out nice and even which seems more likely considering the source of the question.
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