Reply																		
							Thu 28 Oct, 2004 11:04 pm
						
						
					
					
					
						Hello.  I got stuck on this question.  I got the answer.. but I don't know why..  Could someone solve this and explain??  
1.00g of a gaseous compound of boron and hydrogen occupies 0.820L at 1.00atm and 3degrees celcius.  What is the molecular formula for the compound?
Here's the procedure we did:
n=(PV)/(RT)=0.036188mol
Molar Mass= 1g/0.036188mol=27.6335g/mol
So B=2, because two borons can fit in 27.6335g.  What's remaining is the H, so H=6.  So it's B2H6.
  I just don't know why that last step is done (where the borons work for 27.6335g).  Please help!!
					
				 
				
						
														
					
												Your molar mass is the sum of mass contributions from boron and hydrogen; i.e., xB + yH = 27.6335 where B is the atomic mass of boron and H is the atomic mass of hydrogen.   
The atomic mass of boron = 10.8  Therefore, the calculated molar mass can incorporate two boron atoms, which together account for 2 * 10.8 = 21.6 g/mol of the molar mass.  The remainder (27.6335 - 21.6) must come from hydrogen.  Since hydrogen has an atomic mass of 1, 27.6 - 21.6 = 6 => there are 6 hydrogen atoms in the molecule.  The molecular formula is therefore B2H6.
											
					
				 
																
						
														
					
												I have a question about corrosion.  I just did a science lab to determine if salt water would make a piece of steel rust faster than plain water.  I put 7.5mL of salt, 15mL and no salt and observed them for 6 days.  It turned out that all the pieces rusted at the same rate but the rust on the no salt was bright orange while the rust on the slat water pieces was a dull brown.  I would have expected the salt to make it rust faster but that is not what I observed.
Q: Why is the rust on the salt water pieces brown while the rust on the just salt is bright orange?
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