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Thu 28 Oct, 2004 11:04 pm
Hello. I got stuck on this question. I got the answer.. but I don't know why.. Could someone solve this and explain??
1.00g of a gaseous compound of boron and hydrogen occupies 0.820L at 1.00atm and 3degrees celcius. What is the molecular formula for the compound?
Here's the procedure we did:
n=(PV)/(RT)=0.036188mol
Molar Mass= 1g/0.036188mol=27.6335g/mol
So B=2, because two borons can fit in 27.6335g. What's remaining is the H, so H=6. So it's B2H6.
I just don't know why that last step is done (where the borons work for 27.6335g). Please help!!
Your molar mass is the sum of mass contributions from boron and hydrogen; i.e., xB + yH = 27.6335 where B is the atomic mass of boron and H is the atomic mass of hydrogen.
The atomic mass of boron = 10.8 Therefore, the calculated molar mass can incorporate two boron atoms, which together account for 2 * 10.8 = 21.6 g/mol of the molar mass. The remainder (27.6335 - 21.6) must come from hydrogen. Since hydrogen has an atomic mass of 1, 27.6 - 21.6 = 6 => there are 6 hydrogen atoms in the molecule. The molecular formula is therefore B2H6.
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