Using limits to find slopes (ALGEBRA)

y=x^2+2x

What is the slope at (-3, 3)?

It's necessary in this assignment that I use both formulas:

m=lim f(x)-f(a)/x-a
x->a

m=lim f(a+h)-f(a)/h
h->0

I've gotten the slope and the equation of the linear touching down at (-3, 3) using the first formula. I just factored it.

lim (x^2+2x-3)/(x+3)
x->-3

lim ((x-1)(x+3))/(x+3)
x->-3

lim x-1 = -4
x->-3

but in the second formula something is slipping past me. I hate math.

lim f(3+h)-3/h
h->0

lim ((3+h)^2 + 2(3+h)-3)/h
h->0

lim (h^2+8h+12)/h
h->0

Factoring it doesn't help and if I cancel the hs at this point I'm left with 20, which in most states doesn't equal -4.