Triangle Proof, EZ for you guys probly

make F the point where the two medians intersect.

triangle EBD is congruent to EAC (side angle side)

therefore angle EDB = angle ACB

angle DFA = angle CFA (opposite angle theorem)

angle FBC = angle DAF (sum of angles in a triangle)

triangle FBC in congruent to FAD (angle side angle)

side DF = side FC (congruent triangles), so DFC is isoceles

angle FDC = angle FCD (isoceles triangle theorem)

so since angle ADF = angle BCF, and angle FDC = angle FCD, then angle ADC = angle BCD (add the previous 2 together) so the triangle is isoceles (2 equal angles)

cool
uhhhh i think thats right ill check w/ my math teacher, im tryig to compute it with ur equation, but its kinda hard. im guessing you got it right but just to make sure, illt ry it again

i just fond an error, you are never given that DB=AC, so u cant prve the triangels as congruent

youre probably right, i did it quick.......you can do it many other ways though, such as using the fact that a median splits the triangle into 2 triangles with equal areas.

also, try adding in another median, it should be easier

after another quick look over, i dont think you have enough info