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Next number in a sequence

 
 
Gouki
 
Reply Thu 9 Sep, 2004 04:38 pm
I'm currently tangled in my math homework. Can somebody tell me a formula which I can use to determine the "n"th term in a sequence? e.g. 5, 4, 9, 13, 22
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sublime1
 
  1  
Reply Thu 9 Sep, 2004 05:42 pm
Not too experienced in math but it looks like you add the last number to the one previous to it to get the next number. As far as a formula I don't know.
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stuh505
 
  1  
Reply Thu 9 Sep, 2004 06:30 pm
well a recursive equation would be pretty easy to do..

y(1) = 5
y(2) = 4
y(n) = y(n-2) + y(n-1)

are you sure the series isn't supposed to start like 1, 4, 5?
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Gouki
 
  1  
Reply Thu 9 Sep, 2004 07:08 pm
stuh505 wrote:
well a recursive equation would be pretty easy to do..

y(1) = 5
y(2) = 4
y(n) = y(n-2) + y(n-1)

are you sure the series isn't supposed to start like 1, 4, 5?


well, the sequence is infinite. 5, 4, 9, 13, 22, ... and what does the 'y' mean? Does it mean the same thing as 'term?' Also, is that y(n) = y(n-2) + y(n-1) a set equation or is it one for the problem?
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markr
 
  1  
Reply Thu 9 Sep, 2004 07:45 pm
Check this out:
http://www.math.jhu.edu/courses/107/archives/notes/f01coursenotes/node35.html
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stuh505
 
  1  
Reply Thu 9 Sep, 2004 08:38 pm
Quote:
well, the sequence is infinite. 5, 4, 9, 13, 22, ... and what does the 'y' mean? Does it mean the same thing as 'term?' Also, is that y(n) = y(n-2) + y(n-1) a set equation or is it one for the problem?


yes, it is an infinite series...and it's sum (the sequence) is an infinite number.

y(x) is how we define functions, the letters are arbitrary. the first letter (in this case y) is the dependent variable (ie, the output) and x is the independent varaible (ie, the input)

I would think that if you were asked to find an equation for the series you would already have learned about functions...?

anyway, so no, it is not the same as a term. but if you substitute n into the independent variable, the dependent variable will represent the nth term of the series...this is how a discrete function works
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