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Fri 22 Jul, 2016 12:56 am
A-B=5 , B-C=4 and C-A=3 THEN FIND (A^3+B^3+C^3 - 3ABC) /(A+B+C) =?
@ajeet gared,
while A-B=5, B-C=4
then
A-C=9
or
C-A=-9
your third equation (C-A=3) is not true.
@ajeet gared,
..nor is it a quadratic equation.
@fresco,
Just by replacing A and B in the first equation with the values of the next two equation proves there is no solution.
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