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Wed 11 Aug, 2004 02:20 am
Hello !
I have this:
1
3
11
67
And i must found a something what those numbers have common with themselves !!!
Can anyone genius can help me?
They're all prime numbers. That's the first thing that jumps out.
Yep. definitive. They're all prime numbers.
1 isn't prime, but that probably is the "answer."
Those numbers are a passwrod hint. Any other suggestions except they are a prime numbers ? Maybe some other common ?
Try this sequence
I[n]=I[n-1]*2n+(-1)^(n+1)
Where I[0]=1
e.g.
I[0]=1
I[1]=I[0]*2*1+(-1)^2=1*2+1=3
I[2]=I[1]*2*2+(-1)^3=3*4-1=11
I[3]=I[2]*2*3+(-1)^4=11*6+1=67
I[4]=I[3]*2*4+(-1)^5=67*8-1=535
I[5]=I[4]*2*5+(-1)^6=535*10+1=5351
The sequence then becomes
n In
0 1
1 3
2 11
3 67
4 535
5 5351
Rap
hmmm.... there is not this sequence .... but this is right but doesnt work :-/
A prime number is defined as a number having exactly two factors. 1 has only one factor: itself. You don't list the same number as two factors (you don't list the factors of 1 as: 1, 1). Two is, as you said, prime though (1, 2).