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Mon 19 Jul, 2004 08:41 am
The side af a large tent is in the shape of an isosceles triangle whose area is 54ft squared and whose base is 6 feet shorter than twice its height.
Let b = the length of the base, and h = the height.
Area = 54 = (1/2)bh (for any triangle)
2h - b = 6 (base is 6 less than twice the height)
Rearranging the second of these to solve for b, b = 2h - 6.
Now substituting this in the first equation:
(1/2)(2h - 6)h = 54
(1/2)(2h^2 - 6h) = 54
h^2 - 3h = 54
h^2 -3h - 54 = 0
By any of various methods, this quadratic can be factored into (h-9)(h+6).
h must be the positive root which is 9. Now, substituting back into the formula b = 2h - 6, we have:
b = 2(9) - 6 = 18 - 6 = 12.
Therefore, the base is 12 and the height is 9.