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# Picture-Dimensions

Wed 14 May, 2014 12:23 pm
If a picture is placed in a frame 2 inches wide and frame area is 87 square inches, what are picture dimensions?

Let:
L- Length

W- Width

Frame is x larger than width. (Not sure how to calculate).

My solution (not sure):

L X W = LW Total Area of frame and picture.

(L-4)(W-4)= LW - 4W - 4L + 16 in.^2

LW - (LW - 4W - 4L + 16) = 87

4W + 4L = 103

W + L = 25.75

How do I proceed from here?

Thanks.
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contrex

1
Wed 14 May, 2014 02:01 pm
We don't know the width and height of the frame.

Randy Dandy

1
Wed 14 May, 2014 02:31 pm
@contrex,
Length- 10.25 inches
Width- 8.5 inches
raprap

1
Thu 15 May, 2014 10:00 am
@Randy Dandy,
That won't work (too many constraints)

The first equation is correct

W+L=103/4

but if W=10.25=41/4 then L=103/4-41/4= 62/4=15.5

if L=8.5=34/4 then W=103/4-34/4=69/4=17.25

Rap
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Randy Dandy

1
Thu 15 May, 2014 10:47 am
Dimensions of frame:

Length- 10.25 inches *
Width- 8.5 inches *

* 8 x 10 frame.

Frame- 2 inches wide

Frame area- 87 in.^2

Picture dimensions:

Length- 6.5 inches *

Width- 4.5 inches *

* 4 x 6 picture

I was attempting to use the formula to calculate with actually measuring frame and picture.

Which measurement to use for length is x larger than width for frame?

10.25/8.5 = 1.20

8/5/10.25 = .829

10.25-8.5 = 1.75

Randy Dandy

0
Thu 15 May, 2014 02:41 pm
@Randy Dandy,
"I was attempting to use the formula to calculate with actually measuring frame and picture".

Should be without actually measuring. Typo.
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