Sun 20 Apr, 2014 06:39 pm
As the coordinate space is 1:1 it obviously isn't linear (not a straight line segment)
Rap
Using the starting point (0,1) I'd say it's more likely to be exponential.
Why? If y=k^x where k is any real constant---then for x=0 then y=k^0=1
Rap
@Cyrus23,
It is the graph of the function x -> x^2/4 +1, so clearly quadratic.