Weight / Volume of Tank

Forums: Algebra, Meth Mentor
Email this Topic • Print this Page

A stainless steel cylindrical tank has the following dimensions:

Height- 14'
Radius- 6'
Thickness- .25"

Calculate:

A- Weight of the empty tank. Stainless steel weighs 4.538 ounces per cubic inch.

B- Number of gallons the tank will hold. One cubic foot = 7.48 gallons.

What is known:

Dimensions of tank

Tank material weight per cubic inch.

Amount of water per cubic foot.

Want to know:

Weight of empty tank.
Volume of tank.

My solution for B:

Cylinder volume- pi x r^2 x h

3.14 x 6^2 x 14
3.14 x 36 x 14
3.14 x 504
1582.56 = 1583 ft.^3
1583 x 7.48 = 11840.84 = 11841 gallons.

I am unsure how to calculate A.

Topic Stats
Top Replies
Link to this Topic

Type: Question • Score: 0 • Views: 2,815 • Replies: 3

No top replies

@Randy Dandy,

Randy Dandy wrote:

I am unsure how to calculate A.

Assume the tank is capped on both ends. You need total area.
2 caps (pi)(6 squared)x2 = 72 pi
cylinder (pi)x12x14= 168pi
Total area = 240pi
Weight= (240pi)x.25x4.538 ounces

In the real world, if you actually had to weld up this project according to specs, the thickness would be extremely important. The inside/outside diameter of the tank affects the dimensions of the caps. (If inside radius is 6", then outside radius is 6.25")

0 Replies

@Randy Dandy,

The thickness of the steel is much more important that the weight of a cubic inch. Using a Machinist Handbook or a Design Engineers Handbook or a sales catalog from a metal dealer, look of the weight of a square foot of 1/4" steel plate. Extrapolate.

0 Replies

Thanks.

0 Replies

Weight / Volume of Tank

Related Topics

Quick Links

My Account

able2know