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Finding stationary points

 
 
Reply Mon 13 Jan, 2014 11:57 am
F(x,y) = (y^2+y-16)sin(x) find all stationary points classify them


I have found the derivatives and set to equal 0, now I'm stuck

F(x) = cos(x)(y^2+y-16) = 0
F(y) = sin(x)(2y+1) = 0

I could just do with a point in the right direction, maybe my working out is wrong??
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Type: Question • Score: 0 • Views: 1,232 • Replies: 5
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fresco
 
  1  
Reply Mon 13 Jan, 2014 03:08 pm
@Sarahlouise123,
Googling (y^2+y-16)sin(x) will display the stationary points which may be of some help.
Sarahlouise123
 
  1  
Reply Mon 13 Jan, 2014 04:33 pm
@fresco,
I already tried this and but it did not show them, thanks

It is solving the two equations to get the points that I need help with, I have solved one for y then placed that back in but my results do not seem right

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markr
 
  1  
Reply Mon 13 Jan, 2014 08:03 pm
@Sarahlouise123,
Whenever a product equals 0, one or both of the multiplicand and multiplier must equal 0.

For what values of x does cos(x) = 0?
For what values of y does y^2 + y - 16 = 0?

Do the same for the second function.

Since the expressions in x don't share a zero, and the expressions in y don't share a zero, you're going to have to select an x from one function and a y from the other function.
Sarahlouise123
 
  1  
Reply Tue 14 Jan, 2014 12:23 pm
@markr,
Yeah but does cosx = 0 and sinx = 0 not have infinite solutions?
I was at first using x = pi/2 or 3pi/2 but realised there would be more values

Sorry I know I'm probly being stupid , I can solve for y but just cannot see how my answers are stationary points
markr
 
  1  
Reply Wed 15 Jan, 2014 12:38 am
@Sarahlouise123,
Can't there be an infinite number of stationary points?
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