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What's the name of this sequence?

 
 
imapom
 
Reply Wed 14 Apr, 2004 06:16 pm
I remember seeing this somewhere, don't know where, don't know when, but it went something along the lines of

Pi/4 = 1-1/3+1/5-1/7+1/9...

I realise that Pi/4 = 11/14, but does anyone know what this is about? And how the hell does someone get to discover this...??
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Type: Discussion • Score: 1 • Views: 869 • Replies: 6
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gustavratzenhofer
 
  1  
Reply Wed 14 Apr, 2004 06:34 pm
Leibnitz's Formula
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imapom
 
  1  
Reply Wed 14 Apr, 2004 07:06 pm
Thanks for that - I'll have a search around and find out a bit more now I know what I'm aiming for.
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ReX
 
  1  
Reply Sat 1 May, 2004 11:37 am
Is that leibniz's only formula?!
0 Replies
 
patiodog
 
  1  
Reply Sat 1 May, 2004 12:27 pm
If you multiply each term by x raised to the power of the denominator, it's the cosine of x. Dunno how to get from there to pi/4, though. Hmmmm....
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Nulle
 
  1  
Reply Tue 11 May, 2004 01:28 am
patiodog wrote:
If you multiply each term by x raised to the power of the denominator, it's the cosine of x. Dunno how to get from there to pi/4, though. Hmmmm....

Actually, it is not cos(x) but arctan(x) (inverse tangent):

arctan(x) = x - x^3/3 + x^5/5 - x^7/7 + ...
sin(x) = x - x^3/3! + x^5/5! - x^7/7! + ...
cos(x) = 1 - x^2/2! + x^4/4! - x^6/6! + ...

To see that arctan(1) equals pi/4, just apply the definition of arctan to an isosceles right (45-45-90) triangle.

http://mathworld.wolfram.com/RightTriangle.html
http://mathworld.wolfram.com/Trigonometry.html
http://mathworld.wolfram.com/InverseTangent.html
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Zedd
 
  1  
Reply Mon 17 May, 2004 04:34 pm
Oh yea, speaking of series and such...can someone tell me the names of the most commonly used series in Calculus? Thanks. Very Happy
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