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Integral of length of curve

 
 
Reply Wed 20 Nov, 2013 03:45 pm
how can i integrate
x=[integrate from y to 0](sec^2(t)-1)^1/2 dt, -pi/3<y<pi/4
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Type: Question • Score: 2 • Views: 1,502 • Replies: 1
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Brandon9000
 
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Reply Sun 24 Nov, 2013 03:05 pm
@needhelp873,
needhelp873 wrote:

how can i integrate
x=[integrate from y to 0](sec^2(t)-1)^1/2 dt, -pi/3<y<pi/4

It may help to note that the integral of the secant squared is the tangent.
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