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Thu 7 Nov, 2013 09:14 am
You and three other beer lovers have 5 containers, 3, 6, 11, 14 and 16 litres. The 16 litre container is full of beer, can you end up, by pouring, with 4 containers each contaning 4 litres of beer in minimal steps. (probably 17) All containers have an irregular form so no guessing.
@whimsical,
No, I can only work in pints when beer is concerned.
@Lordyaswas,
O, I misspelled pint, I thought is was spelled litre. Sorry about that.. :-)
@whimsical,
Hi Whim!
17 is minimal. Here's a solution:
0 0 0 0 16
3 0 0 0 13
3 6 0 0 7
3 0 0 6 7
3 6 0 6 1
3 0 0 12 1
1 0 0 14 1
1 6 0 8 1
1 0 6 8 1
1 6 6 2 1
1 1 11 2 1
1 1 0 13 1
1 0 1 13 1
1 6 1 7 1
3 4 1 7 1
0 4 1 7 4
3 4 1 4 4
0 4 4 4 4
@markr,
Thanks Mark,
It's good to see your still frequenting able2know.
Whim
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