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Find the eigenvectors
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Eigenvectors
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LOLA SOLNCE
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Sun 30 Jun, 2013 08:28 am
(1−λ)((2−λ)(1−λ)−1)+(−1)(1−λ)=−λ3+4λ2−3λ
−λ3+4λ2−3λ=−(λ−3)(λ−1)λ=0
eigenvalues found:
λ1=0, λ2=1, λ3=3
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Type: Question • Score: 0 • Views: 580 • Replies: 1
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Kolyo
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Sun 30 Jun, 2013 06:54 pm
@LOLA SOLNCE,
The next step is to find a vector v for each λ, such that Av = λv.
This means finding v such that (A - λI)v = 0.
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