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trig area problem
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Air721
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Sun 24 Feb, 2013 11:22 am
what does a= when b=4 c=10 A=27
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Type: Question • Score: 0 • Views: 873 • Replies: 2
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fresco
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Sun 24 Feb, 2013 01:17 pm
@Air721,
c^2=a^2+b^2-2abcosC ....COSINE RULE
=a^2+b^2-2ab sqrt (1- sin^2 C) .....FROM cos^2+sin^2=1
and sin C=2A/ab from A=(1/2) ab SinC...AREA OF TRIANGLE
so c=sqrt[ a^2 + b^2 - 2ab sqrt (1 - (2A/ab)^2)
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fresco
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Sun 24 Feb, 2013 01:39 pm
@fresco,
Sorry, there is a final
]
missing at the end of that ...
c=sqrt[ a^2 + b^2 - 2ab sqrt (1 - (2A/ab)^2)]
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