1
   

Calculus problem help

 
 
Reply Mon 4 Feb, 2013 09:20 am
So this is the function f(x)=(x+4)/(x^2+5x+4)

Can anyone confirm that I got the right answers

1. Domain: All real nos except -4 and -1

2. Range:(-∞,-1/3)∪(-1/3,∞)


3. For critical points I get x=-4 and x=-1 but since the function is not defined at these points so no critical points right?

4. The increasing/decreasing interval for the function will be decreasing entirely

5. At x=-4 the function wont be continuous but how am I supposed to show it in mathematical form

f(-4)=undefined
limit(x approaches -4)=undefined

so not continuous,is this the correct way?

6. The inflection point I got was x=-1 but since again the function is also undefined at this point so there will be no inflection point

7. For concavity the function will have concave down decreasing from (-oo,-1) and concave up decreasing from (-1,+oo)
  • Topic Stats
  • Top Replies
  • Link to this Topic
Type: Question • Score: 1 • Views: 1,162 • Replies: 1
No top replies

 
Kolyo
 
  1  
Reply Sat 9 Feb, 2013 12:50 pm
@hamza4best,
It's been awhile Hamza, but I just saw this...

hamza4best wrote:

So this is the function f(x)=(x+4)/(x^2+5x+4)
First thing to note is that f(x) = 1/(x+1), except at x = -4
Can anyone confirm that I got the right answers

1. Domain: All real nos except -4 and -1
Right.
2. Range:(-∞,-1/3)∪(-1/3,∞)
I don't believe 0 is part of the range.

3. For critical points I get x=-4 and x=-1 but since the function is not defined at these points so no critical points right?
Right.
4. The increasing/decreasing interval for the function will be decreasing entirely
Right.
5. At x=-4 the function wont be continuous but how am I supposed to show it in mathematical form

f(-4)=undefined
I would stop there...
limit(x approaches -4)=undefined
...because the limit exists as x approaches -4. It is -1/3.

so not continuous,is this the correct way?
In order for a function to be continuous at a point the value at the point has to equal the limit as the function approaches the point. When the function has no value at that point this cannot happen.

6. The inflection point I got was x=-1 but since again the function is also undefined at this point so there will be no inflection point
Right.
7. For concavity the function will have concave down decreasing from (-oo,-1) and concave up decreasing from (-1,+oo)
Right.
0 Replies
 
 

Related Topics

Amount of Time - Question by Randy Dandy
logical number sequence riddle - Question by feather
Calc help needed - Question by mjborowsky
HELP! The Product and Quotient Rules - Question by charsha
STRAIGHT LINES - Question by iqrasarguru
Possible Proof of the ABC Conjecture - Discussion by oralloy
Help with a simple math problem? - Question by Anonymous1234567890
How do I do this on a ti 84 calculator? - Question by Anonymous1234567890
 
  1. Forums
  2. » Calculus problem help
Copyright © 2024 MadLab, LLC :: Terms of Service :: Privacy Policy :: Page generated in 0.11 seconds on 12/23/2024 at 12:38:30