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help needed urgently with limits...

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kartik12345
 
Reply Fri 23 Nov, 2012 01:20 am
lim x--->0 cos 3x-cos 7x / x^2 help needed to evaluate it
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Type: Question • Score: 0 • Views: 669 • Replies: 2
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fresco
 
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Reply Fri 23 Nov, 2012 11:40 am
@kartik12345,
as x...>0, cos ax...> 1 and x^2.....>o

so it looks like

1-1/o =
1-infinity =
-infinity

but you could do with someone like makr to confirm.
markr
 
  1  
Reply Fri 23 Nov, 2012 01:18 pm
@fresco,
That's correct. However, if the expression should have been (cos(3x)-cos(7x))/x^2, then you need to apply L'Hôpital's rule a couple of times.

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