Crap. I can't figure this out. (Math)

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1160 pieces of a box 35.5 x 31.5 x 21.5 fills a container.
So does
747 pieces of a box 41.5 x 38.5 x 23.5

or 830 pieces sized 41.5 x 38.5 x 22
and
finally
480 pieces sized 47.5 x 45.5 x 27.5.

All those will fill a container.

Okay.
How do I figure out what combination, using all the sizes of boxes, fills the container?

I know its about cubic area but I'm stumped. All those pieces times (size box) should make the same cubic area, right?

I want to be able to tell a customer "If you buy X of this size and y of that size and Z of that size and d of that size, you'll have a container. and what's the fewest he has to buy. ??
Joe(gah)Nation

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Type: Question • Score: 9 • Views: 4,648 • Replies: 72

[+3] - raprap - 04/18/2012Went back and looked at the question--the fewest of each type would be 1 layer of A, 1 layer of B, 1 layer of C and the rest of D 1/10+1/9+1/10=9/90+9/90+10/19=28/90=14/45...

View best answer, chosen by Joe Nation

@Joe Nation,

isn't there some little oriental guy there you can ask?

I hear they are great with the math stuff...

(32 car lifts to a container)

0 Replies

@Joe Nation,

The fewest he has to buy is 480....

1 Reply

@DrewDad,

No, Drew, he has to buy some of all the sizes.
How many of each size?

Joe( I M THICK)Nation

1 Reply

@Joe Nation,

OK. It has to completely fill the container, or can there be a little room left?

2 Replies

@DrewDad,

Sure. There can be room left, some.

That's not a problem.

Joe(the problem is with my head)Nation

1 Reply

@DrewDad,

Yikes. When you multiply out the size of the boxes by the number of boxes per container, you get different total cubic sizes.

2 Replies

@Joe Nation,

What size container are you using?

http://www.schumachercargo.com/shipping-container-sizes.html

1 Reply

@DrewDad,

You do? Crap.
Okay.
Assume that the largest one, which ever it is, fills the container up the most?
Then what?

And what formula did you use to figure out the cubic area of each of the sizes?
That's where I was getting stuck.

Joe( if a fly flies from one windshield....zzzzzzz.)Nation

1 Reply

@DrewDad,

Code:



Box type          Per container         Cubic size of box       Cubic size used for full container

A                       1,160               24,042.375          27,889,155

B                         747               37,547.125          28,047,702.375

C                         830               35,150.5            29,174,915

D                         480               59,434.375          28,528,500

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@Joe Nation,

Multiply the dimensions of the box. Height x Length x Depth = cubic volume of the box

By my calculations (you should check my math) the difference between a "full container" of D and a "full container" of C is pretty big.

You should have enough room in a "full container" of D to fit in at least one of the rest of the sizes of boxes.

Is this some kind of test? I would think that the boxes would come in pallet loads, and you'd know how many pallets to a container.

0 Replies

@ehBeth,

Dunno.
The assumption is whatever kind it is is filled by the 1160 x(35.5cm x 31.5cm x 21.5cm) boxes.

So.
What is that cubic area anyway?
Once you multiply 35.5x31.5x21.5
what do you divide by to get the cubic meters?

Joe(show your work)Nation
Shocked

1 Reply

The product can be palletized but these numbers come from the dock which says the boxes are just stacked in.

Joe(thanks for your help)Nation

1 Reply

@Joe Nation,

It appears to me that every D can be filled with an A, B, or C.

Matryoshka boxes for the win!

2 Replies

@DrewDad,

(You can keep the bonus when you present that solution to your bosses.)

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@Joe Nation,

Just add together all the sides of the boxes. e.g. 35.5+41.5+41.5+47.5, and do the same with the other two sides to get the total size of the box. Then add up all the pieces to get your total.

1 Reply

@cicerone imposter,

Er.... no.

One does not add in order to get cubic volume.

2 Replies

@DrewDad,

ooops, you're right. My calc will not work.

0 Replies

@DrewDad,

ok, some little oriental guy besides cicerone...

Wink

0 Replies

@DrewDad,

Erm. I'm not explaining this correctly.

The customer has to buy a container full of some As, some Bs, some Cs and some Ds. Some of each kind.

The customer wants to know what's the fewest of each kind he has to buy ABCD in order to get his mixed order?

Is there a way to figure that out?

XA+YB+ZC+WD= F

or are there too many variables?

I'd have to make a whole spreadsheet of all of the different combinations that would still add up to F.

(I could do that.)

Joe(my head hurts)Nation

1 Reply

Crap. I can't figure this out. (Math)

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