0
   

How much?

 
 
Reply Wed 4 May, 2011 06:08 am
If a perfectly round and perfectly hard ball is resting on a perfectly flat and perfectly hard surface, how much of the ball is in contact with the surface?
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Type: Discussion • Score: 0 • Views: 1,507 • Replies: 13
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engineer
 
  1  
Reply Wed 4 May, 2011 06:24 am
@hamilton,
One
hamilton
 
  1  
Reply Wed 4 May, 2011 05:15 pm
@engineer,
??? one what?
engineer
 
  2  
Reply Wed 4 May, 2011 07:46 pm
@hamilton,
One point.
fresco
 
  1  
Reply Wed 4 May, 2011 11:43 pm
@engineer,
Smile
0 Replies
 
hamilton
 
  1  
Reply Thu 5 May, 2011 06:03 am
@engineer,
...
how much is that one point, though?
dadpad
 
  1  
Reply Thu 5 May, 2011 06:12 am
@hamilton,
How big is the ball?
hamilton
 
  1  
Reply Thu 5 May, 2011 08:14 am
@dadpad,
would it matter?
0 Replies
 
fresco
 
  1  
Reply Thu 5 May, 2011 11:58 am
@hamilton,
Steady now.....you are getting into the mathematics of "different sized infinitessimals" which put Georg Cantor into a mental institution !

Maths is full of ridiculously "perfect" objects like "flat surfaces" and "non-deformable spheres". They are merely models which give approximations to real life statics and dynamics.
0 Replies
 
engineer
 
  1  
Reply Thu 5 May, 2011 12:03 pm
@hamilton,
The one point is infinitely small.
0 Replies
 
raprap
 
  1  
Reply Thu 5 May, 2011 01:13 pm
The intersection of a plane and a sphere chosen at random in a space is either zero (no intersection), a point, or a circle smaller than or equal to the diameter of the sphere. Sounds like your case is one point.
hamilton
 
  1  
Reply Thu 5 May, 2011 07:14 pm
@raprap,
ok. how would the third one work out. ive never heard it put like that.
engineer
 
  1  
Reply Thu 5 May, 2011 07:16 pm
@hamilton,
Picture a plane going through the ball. The intersection is a circle.
hamilton
 
  1  
Reply Thu 5 May, 2011 07:20 pm
@engineer,
ooohhh.... ok. i see now. i was thinking of a 2d plane, but your talking 3d. ok.
0 Replies
 
 

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