1
   

Physics help needed

 
 
Reply Fri 2 Jan, 2004 04:13 pm
1. A 10.0 kg mass, m1, on a frictionless table is accelerated by a 5.0 kg mass, m2, hanging over the edge of the table. What is the acceleration of the mass along the table?

2. A bell ringer decides to use a bowling ball to ring the bell. He hangs the 7.3 kg ball from the end of a 2.0 m long rope. He attaches another rope to the ball to pull the ball back, and pulls it horizontally until the ball has moved .60 m away from the vertical. How much force must he apply?

3. Tim, mass 42.00 kg, is riding a skateboard, mass 2.00 kg, traveling at 1.20 m/s. Tim jumps off and the skateboard stops dead in its tracks. In what direction and with what velocity did he jump?

Any ideas?
  • Topic Stats
  • Top Replies
  • Link to this Topic
Type: Discussion • Score: 1 • Views: 1,627 • Replies: 4
No top replies

 
Wilso
 
  1  
Reply Sat 3 Jan, 2004 07:08 am
This looks very like a homework question. While people on this site don't mind giving advice, they generally don't like doing people's homework for them. So here's some tips. Looks like very basic physics, so I'd suggest all conditions will be ideal ie, no friction or air resistance.
Draw diagrams of the problems.
Force (Newtons) = Mass (kg) * acceleration (m/s^2)

Acceleration due to gravity is 9.8m/s^2

v=u + at
v (final velocity-m/s)
u (initial velocity- m/s)
a (acceleration)
t (time)

There should be enough information there for you to work out the answers. At least have a go, and post what you worked out. It's been a couple of years, so I don't know if I can do even this simple stuff any more, but if not myself, someone here will be able to do it.
0 Replies
 
Slinky8844
 
  1  
Reply Sun 4 Jan, 2004 01:44 pm
I think I may have figured one out.. does this make sense?
3. Tim, mass 42.00 kg, is riding a skateboard, mass 2.00 kg, traveling at 1.20 m/s. Tim jumps off and the skateboard stops dead in its tracks. In what direction and with what velocity did he jump?
-->I think that this problem has to do with conservation of momentum, and that I can apply the formula m1v1=-m2v2. (42.00 kg) (v1)= -(2.00 kg) (1.20 m/s)---> (42.00 kg) (v1)=-2.4 kg-m/s--> v1=-.06 m/s. **Tim jumps in the negative direction .06 m/s. Is that right? I feel like there's something more to it that I'm missing.
0 Replies
 
Wilso
 
  1  
Reply Sun 4 Jan, 2004 01:52 pm
I just got out of bed and have got to go to work. I'll check in this arvo.
0 Replies
 
Wilso
 
  1  
Reply Sun 4 Jan, 2004 11:05 pm
1. I'm assuming that the 2 masses are joined. The acceleration will be due solely to gravity. ie, 9.8 m/s^2.

Have to think about the next two.
0 Replies
 
 

Related Topics

Evolution 101 - Discussion by gungasnake
Typing Equations on a PC - Discussion by Brandon9000
The Future of Artificial Intelligence - Discussion by Brandon9000
The well known Mind vs Brain. - Discussion by crayon851
Scientists Offer Proof of 'Dark Matter' - Discussion by oralloy
Blue Saturn - Discussion by oralloy
Bald Eagle-DDT Myth Still Flying High - Discussion by gungasnake
DDT: A Weapon of Mass Survival - Discussion by gungasnake
 
  1. Forums
  2. » Physics help needed
Copyright © 2025 MadLab, LLC :: Terms of Service :: Privacy Policy :: Page generated in 0.05 seconds on 01/15/2025 at 11:09:04