@Surena,
@surena
i am assuming ur problem is like: integral [(5lnx+3)/x]dx.
u can separate it like Integral[(5lnx/x)dx+ (3/x)dx]
for the first term let lnx = u
differtiate gives wrt x, dx/x = du
so, 5lnx/x becomes 5*u du. now u can do it.
and the second term has direct integral i.e 3 lnx.
hope this helps.
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