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# Logarithms

Wed 14 Apr, 2010 03:36 am
How can we calculate log(2).I want it to explain to my students and to know the procedure of finding log values.
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fresco

1
Wed 14 Apr, 2010 12:22 pm
@ro14,
You have not stated the base b for your logarithms.

In general, If logb(2) = x then b^x =2 or x=2^(1/b)

E.g log8(2)=0.333 because 2=8^(1/3) or 2^3 =8
ro14

1
Thu 15 Apr, 2010 02:54 am
@fresco,
Base is 10, as base 10 is common.
fresco Selected Answer

2
Thu 15 Apr, 2010 11:03 am
@ro14,
As far as I know there is no iterative procedure for calculating logs in base 10.

Try this approximation method.
http://www.karlscalculus.org/l6_3-2.html
fresco

1
Thu 15 Apr, 2010 11:11 am
@fresco,
(But a google search may indicate that there are iterative procedures I am unaware of).
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nycfunction

1
Wed 26 May, 2010 06:58 am
@ro14,
log(base 10) 2 = x

General Formula: log(base b) (a number) = x

This can be written as 10^x = 2

Now take the natural log of both sides.

Can you take it from here?
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