Logarithms

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How can we calculate log(2).I want it to explain to my students and to know the procedure of finding log values.

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@ro14,

You have not stated the base b for your logarithms.

In general, If logb(2) = x then b^x =2 or x=2^(1/b)

E.g log8(2)=0.333 because 2=8^(1/3) or 2^3 =8

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@fresco,

Base is 10, as base 10 is common.

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@ro14,

As far as I know there is no iterative procedure for calculating logs in base 10.

Try this approximation method.
http://www.karlscalculus.org/l6_3-2.html

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@fresco,

(But a google search may indicate that there are iterative procedures I am unaware of).

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@ro14,

log(base 10) 2 = x

General Formula: log(base b) (a number) = x

This can be written as 10^x = 2

Now take the natural log of both sides.

Can you take it from here?

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Logarithms

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