Chemical Equalibrium... help??

Me too.

any ideas?

I hope this will assist you to come to some understanding of the problem.

http://crab.rutgers.edu/~maslen/Courses/PChemII/7_Equilibrium/Equilibrium_Homework_Solutions.pdf

In order to get two moles of NH3, you need three moles of H2 and one of N2. You have four moles of NH3, so how many moles of H2 and N2 were required to make that? Add that to what is still there and you will have the original concentrations of those two gases.

After I figure out how many moles are required to make 4 of NH3, how do I add that to what is still there??

Even after the reaction reached equilibrium, you had 5M of H2 and 8M of N2 left. After you calculate the number of moles of H2 and N2 that reacted, you have to add 5 and 8 to the totals to see what you started with.