@joefromchicago,
You are way off joe.
The answer is clearly less then 26 to 1.
Consider the probability there is zero red cards in my half (i.e. all are black)
Then consider the probability that there are one red card in my half (and the rest are black).
The consider three red cards... and four
Continue that sequence until there are 26 red cards (and no black cards).
Two things are clear
1) The sum of all of these 26 different probabilities is 1.
2) That there are 13 red cards in my half is the most likely outcome.