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Mon 31 Aug, 2009 10:20 pm
How many moles of iodine are produced from 7.00 moles of chlorine, according to the equation shown?
3Cl2(g) + 2FeI2(s) --> 2FeCl3(s) + 2I2(g)
A 4.67 mol
B 10.5 mol
C 4.4 mol
D 1185.25 mol
@saisissezlejour,
A 4.67, the ratio between Chlorine and iodine is 3/2 or 1.5... So if you have 7 moles of chlorine you will need 7/1.5 moles of iodine to balance the equation... 7/1.5= 4.6666666 or 4.67
You can also just do 7/3 = 2.33333 then multiply by 2 (for the 2 moles of iodine) to get 4.67
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