Kayyam, Thanks for the reply.
Re: Quote:I'm not sure what you mean by "appear exactly the same". Certainly a water molecule in the vapor phase would be undergoing different vibrational modes than one in any of the ice phases. This would be visually apparent (if you could actually see it).
Both my initial and 2nd post take into account "different vibrational modes" via my reference to their energy states. The phrase "appear exactly the same" references the ideal situation where we take "snapshots", in any given instant of time, of three separate molecules of water, each in different physical states of liquid, gas, and solid respectively. Given that all molecules are of the common type that make up the majority of the population of water (all isotopes of all atoms are equal ) and the "snapshot" effect eliminated the energy state so that we could clearly see only the atomic structure of each molecule they would be identical in appearance. Thus the point of my original post: the only
difference between the said molecules would be their energy states.
This, of course is a story told with the molecular stance in mind. If we were to descend to that level of quantum physics and compare, all bets would be off, even if all three molecules were from the same physical state, say liquid water, a gander at atomic structure may reveal an electron or two "out of place". But what are the odds, eh?
JM