aman
 
Reply Fri 11 Apr, 2008 09:32 am
Sorry , if it has been already posted. What is the 0^0 and why?
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Type: Discussion • Score: 1 • Views: 695 • Replies: 8
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Miller
 
  1  
Reply Fri 11 Apr, 2008 12:33 pm
0^0 = 1
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markr
 
  1  
Reply Fri 11 Apr, 2008 10:13 pm
0^0 is undefined.

http://mathworld.wolfram.com/Zero.html
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aman
 
  1  
Reply Fri 11 Apr, 2008 10:31 pm
Miller wrote:
0^0 = 1

Please proove how?
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raprap
 
  1  
Reply Fri 11 Apr, 2008 11:19 pm
markr is right

0^0 is indeterminate.

As a second source (Dr Math) alluded, any number n^0, except 0, can be interoperated as a logarithm (mathematical transcendentalism)
log(basen)(n^0)=0*1=0
and since n^0=1
for any number except 0
Consider logarithms
log(basen)X as n -> 0=infinity
then log(base0)= 0*infinity
which is as indeterminate as 0/0.

So 0^0, like 0/0, is undefined/indeterminate


Rap
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aman
 
  1  
Reply Fri 11 Apr, 2008 11:52 pm
How about this:
http://mathforum.org/dr.math/faq/faq.0.to.0.power.html
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aman
 
  1  
Reply Mon 14 Apr, 2008 08:19 am
http://mathforum.org/dr.math/faq/faq.0.to.0.power.html - this website is telling 0^0 is 1. Someone tell me about this!
0 Replies
 
markr
 
  1  
Reply Mon 14 Apr, 2008 10:28 pm
It doesn't definitively state that 0^0 = 1.

It uses statements like:

"0^0 = 1 seems to be the most useful choice for 0^0."
"This means that depending on the context where 0^0 occurs, you might wish to substitute it with 1, indeterminate or undefined/nonexistent."
"The following is a list of reasons why 0^0 should be 1."
"Consensus has recently been built around setting the value of 0^0 = 1."
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Kayyam
 
  1  
Reply Mon 14 Apr, 2008 11:57 pm
0^0 = lim(x->0) x^x
0 Replies
 
 

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