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Tue 4 Mar, 2008 12:02 pm
How do i go about using the Gaussian Lens Equation ( 1/object + 1/image = 1/focal length) given the following problem:
a diverging lens has a focal length of -4.0cm. If an object is placed 8.0cm from the lens, how far from the lens is the image?
you get 0.125cm + 1/i = .-25cm
solving for 1/i you get -0.375cm
solving for i you get -2.6666 cm
since the distance is a negative number it means the image is non-real (virtual) and on the same side as the image itself.
Any focal length that is negative means you have a divergent lens.
perfect. thanks a lot man
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