1
   

two coducting spheres

 
 
Reply Tue 22 Jan, 2008 03:31 am
Two conducting spheres of different sizes are at the same potential. The radius of the larger sphere is four times larger than that of the smaller sphere. If a total charge Q is placed on this system, what fraction of Q sits on the larger sphere?

shouldn't it be 1/4? q1 is 1/4 of q2 if i make kq1/r1=kq2/r2, where r1 is r2/4
  • Topic Stats
  • Top Replies
  • Link to this Topic
Type: Discussion • Score: 1 • Views: 661 • Replies: 5
No top replies

 
onthestreet
 
  1  
Reply Tue 22 Jan, 2008 04:23 am
The ultimate two conducting spheres of different sizes are the Sun and the Earth, God and man, of the same potential, but the former has a much greater radius. The total charge of the smaller sphere is recrued from the larger. Therefore the fraction is one and the same. The potential becomes the same as the charge.

Street
0 Replies
 
englishnewb
 
  1  
Reply Tue 22 Jan, 2008 04:46 am
... i dont get what ur saying..
0 Replies
 
DrewDad
 
  1  
Reply Tue 22 Jan, 2008 08:23 am
The electrons/charge will be distributed evenly over the surface area.
0 Replies
 
englishnewb
 
  1  
Reply Tue 22 Jan, 2008 12:39 pm
but why tho, shouldn't the smaller size get more charge?
0 Replies
 
DrewDad
 
  1  
Reply Wed 23 Jan, 2008 10:41 am
The electrons repel each other equally.

Think of it as water pressure. Two lakes connected by a canal are going to equalize at the same level. Two balls connected by a conductor are going to equalize at the same electrical charge.
0 Replies
 
 

Related Topics

Evolution 101 - Discussion by gungasnake
Typing Equations on a PC - Discussion by Brandon9000
The Future of Artificial Intelligence - Discussion by Brandon9000
The well known Mind vs Brain. - Discussion by crayon851
Scientists Offer Proof of 'Dark Matter' - Discussion by oralloy
Blue Saturn - Discussion by oralloy
Bald Eagle-DDT Myth Still Flying High - Discussion by gungasnake
DDT: A Weapon of Mass Survival - Discussion by gungasnake
 
  1. Forums
  2. » two coducting spheres
Copyright © 2025 MadLab, LLC :: Terms of Service :: Privacy Policy :: Page generated in 0.04 seconds on 06/22/2025 at 11:11:35