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Tue 1 Jan, 2008 05:18 pm
Sorry that I'm asking a lot of questions.
What would the operation be for this problem?
Suppose that 6 machines can complete a given task in 2 days. If there are 4 machines, how many days would it take them to finish the same task?
As a percent how many fewer machines does 4 represent?
What?
Now you have just confused me....
How many hours it takes for each machine is an unneeded step.
I still don't understand.
I'm really really really sorry.
Contrition is good for the soul.
You have won the $100 and do not need to pass "Go".
What don't you understand?
You gave me more questions.
Couldn't you have just given the operation on what I am suppose to do?
Like:
X+y= ???
Or something.
I don't understand word problems enough as it is.
If there were 3 machines it would take 4 days (half as many machines = twice as much time). So if there were 4 machines you know it's going to be more than 2 days and less than 4 days, right?
x : y
6 = 2
5 = ?
4 = ??
3 = 4
x1/x2 = y1*y2
6/3=2; 2*2=4
6/4=1.5; 2*1.5=
I mentioned it on another thread already - I still think, understanding
the rule of three would be some help (like it was for others since more than 200 years).
Chum wrote-
Quote:What good would that do?
You never know Chum with Leaka asking the questions.
He needs to understand the basic interrelations of ratios, otherwise that dog won't hunt.
Leaka wrote:You gave me more questions.
Couldn't you have just given the operation on what I am suppose to do?
Like:
X+y= ???
Or something.
I don't understand word problems enough as it is.
You need to speak to a MATH teacher and get your fundamentals sorted out.
You decrease your machine number from 6 to 4:
6/4= 1.5
If you decrease the number of your machines, you'll have to work each machine for a longer time.
How long a time?
1.5 X 2 (days) = 3 days with 4 machines.
bit obvios!
2 divided by 3 times two.
you seem to be fairly good at algebra so hopefully this will help
the first statement 'Suppose that 6 machines can complete a given task in 2 days' can be writen as a equation
z repressent the percentage of the task that is completed by one machine in one day
2 x 6z = 100 (2 is there because this is how long it takes the machines)
so if the formula is rearranged
2 x 6z = 100
6z = 100 ÷ 2
6z = 50
z = 50 ÷ 6
z = 8.333
this shows each machine completes roughly 8% of the task in one day
a new formula can be made from the question 'If there are 4 machines, how many days would it take them to finish the same task?'
d repressents the number of days it takes
d x 4z = 100
at first this looks problematic. however we already know that z is 8.3
d x (4 x 8.333) = 100
d x 33.333 = 100
now by rearranging the equation we can get d (the number of days it takes)
d = 100 ÷ 33.333
d = 3
this shows that it takes 3 days for 4 machines to complete the task
sorry if this isnt helpful, but im not a teacher. u should really just ask ur school teacher for a little help. im sure they wouldnt mind, they would be glad that someone is actually interested in their class
The above is an excellent explanation. However, it's not too simple for a young student who's having problems with math.
The best way to teach math is to make it fun and easy.