Math problem please help as soon as possible thank you

Why can't it be zero?

Re: Math problem please help as soon as possible thank you
Using this equation:


should not give you this result:


Y=-1+2

Using the commutative property:

Y=2-1

Y=???

Re: Math problem please help as soon as possible thank you
Your value of y for x = 1 looks wrong to me.

y = -X + 2

Using X = 0

X = 0
y = -0 + 2
y = 2

Using X= 1

x = 1
y = -1 + 2
y = 1

Using X = 2

x = 2
y = -2 + 2
y= 0



Who says? There is a zero line on the graph, that's where the point goes.

It can't be zero because after I place the points you're suppose to make a complete diagonal line after graphing the points.

But it doesn't matter thank you for the help I fixed it, but now I'm stuck on another one....

Leila runs 10 miles in 75 minutes, how many miles would she run in 78 minutes?

I'm stcuk because I don't know what operation I should do.

Figure out how many miles she runs in a minute using the information you have. Then use that to calculate how many additional miles she runs in the extra three minutes.

Or, set it up as a ratio:

75/10 = 78/Y

cross-multiply 78*10 = 75*Y

Solve for Y 780/75 = ???

But it does make a diagonal line!!! In fact it needs to be zero to make a straight diagonal line!





Huh??



The distance she runs, compared to 10 miles, is going to equal 78 compared to 75

distance = 10 x (78/75)

That doesn't seem right contrex.

10 x (78/75)= 10.4

That doesn't seem right when you calculate it out.

Multiplication is vexation;
Division is as bad;
The Rule of Three doth puzzle me,
And Practice drives me mad.

I got 10/75 = .1333
.1333 x 78 = 10.3974 or 10.4

That looks right to me, as does contrex's graph. If you just go by the x and y intercept you get his graph, so it has to be right. The problem with your calculations is that your second point is incorrect and should be (1,1) and not (1,-1).

Like I said before.

Putting the running problem into words, isn't it just obvious that if she runs 10 miles in 75 minutes, that the distance she runs in 78 minutes is going to bear the same relation to 10 miles as 78 does to 75? I find it helps sometimes to put the problem into words.

78/75 = 1.04
1.04 x 10 = 10.4

The answer is 10.4 miles, Leaka.

you wrote,



But "calculating it out" is what I and others have done! What answer do you get?

Leaka, maybe you should talk to your teacher?

I got 10.4, but it doesn't seem right.

Like I feel I'm going to get it wrong.

I do an independent computer math. Its called Aleks.
You can check it out at:

aleks.com

All right now I'm doing computations of a circle graph.

If the amount budgeted of House 23%, Food 19%, and Insurance 9% combined is 40,800, what is the total family income?

.23+.19+.09= .51
.51t= 40,800
40,800/.51= 80,000

or

.23+.19+.09= .51
.51 x 40,800= 20,808

Aha! Now I understand the problem. It was exactly the same for me at school doing mathematics. Be confident, you sound like a clever person, you just need to practise to get more confident.

If the amount budgeted of House 23%, Food 19%, and Insurance 9% combined is 40,800, what is the total family income?

23 + 19 + 9 = 51

51 % of family income is 40,800

family income is 100/51 x 40,800

= 80,000



You got it right first time! But you don't know why, I suspect.



If you are just guessing how to do it, maybe you need to tell your teacher?

I wasn't guessing.

I over think things.

I know why I got it right.

They were asking for the total. And we were searching for the total

I'm guessing it's hard to do an online independent math course without the benefit of peers and an accessible teacher. We can be your peers for a while if you need to keep bouncing things off of people.

I think one of the benefits of having a teacher can be that he or she can tailor the teaching to you as an individual. I was lucky enough, at one time in my schooldays, to have a good teacher who showed me that maths is not just for "clever" people, that anyone can do it. In particular he pointed me towards a certain way of thinking about maths and solving arithmetic problems. He showed me that there are a number of "tricks" that you can do to make it easier to be sure you are on the right track, and thus build confidence.

Obviously everybody is different and what works for one person may not be right for another person, but one of the most valuable of these, for me, was the idea of trying to speak the problem in words, either in your head or out loud if nobody is around. That way the problem is not just a mess of figures and x's and y's on a piece of paper.

For example, that running 10 miles question. I would say to myself, "Let's see... Leila runs 10 miles in 75 minutes. How far will she run in 78 minutes? Well, 78 is not much more than 75, so it will only be a little bit further." Now I have a feel for what the answer is going to look like. A little bit more than 10 miles. Now I have to work out just how much that little bit is. I can see that it will be 3/75 (because 78-75=3) times 10 miles. Now I put 3/75 in the calculator, and out comes 0.04. Multiply that by 10 to get miles and I have a further distance than 10 miles of 0.4 miles. So she runs 10.4 miles.

Actually, I would have chosen to put the problem a bit differently. In real life, as everybody knows, if you have just run 10 miles you are probably not going to run as fast as you did at the start. So immediately we are getting a bit unreal. I would ask something like "A loom in a textile factory makes 10 metres of cloth on 75 seconds. How much will it make in 78 seconds?"

The household expenses one works the same way. I add up the percentages in my head or on a calculator or with pencil and paper, and I can see that the money spent on house, food and insurance is 51% of household income. I say to myself, "Fifty-one percent is just a shade over half, so the total household income is going to be around twice 40,800, in fact a bit less" Now I have an idea of the size of the answer - a bit less than 81,600.