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Mon 27 Aug, 2007 08:20 pm
Here's the problem:
I am 900 more than the greatest possible 4-digit even number that can be made using the digits 1, 4, 2, 5.
What number am I?
Even number...Tico, that's the catch.
Here's a couple of more:
1) In a 4-digit number, the two greatest place-value digits are 2. The sum of the ones and tens digits is 14. What numbers are possible?
2) If the number 2, 794 has ten thousands digit that is 2 times the ones digit, what is the new number? Explain.
1) 5--four dugit number is 22xy. x+y=14. Solution dyads are (5,9)(6,8)(7,7)(8,5)&(9,5) for 2259,2268,2277,2285 & 2295.
2) 82,794=2,794 + 2*4*10,000
Rap
raprap wrote:1) 5--four dugit number is 22xy. x+y=14. Solution dyads are (5,9)(6,8)(7,7)(8,5)&(9,5) for 2259,2268,2277,2285 & 2295.
2) 82,794=2,794 + 2*4*10,000
Rap
And a 4th grader has to know that?
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