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Find Intercepts of the Circle

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usn0814
 
Reply Mon 10 Aug, 2026 05:08 am
Precalculus
Michael Sullivan
Edition 10
Chapter 1, Section 1.4

Find the intercepts, if any, of the circle.

36. 3x^2 + 3y^2 - 12y = 0
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Type: Question • Score: 0 • Views: 98 • Replies: 2
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izzythepush
 
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Reply Mon 10 Aug, 2026 06:46 am
@usn0814,
Charles the bald
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eigenvalue
 
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Reply Mon 10 Aug, 2026 07:01 am
@usn0814,
36. To solve for x-intercepts, set y=0
3x^2+3(0)-12(0)=0
x^2=0
x=0
The x-intercept is (0,0)

To solve for y-intercepts, set x=0
3(0)+3y^2-12y=0
y(y-4)=0
y=0 and y=4
The y-intercept is (0,0) or (0,4)
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