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Vector to Polar Form

 
 
Reply Wed 3 Oct, 2018 01:46 pm
I added (2.0i+14j) + (-4.2i+16j) to get 30j-2.2i. What is the answer in polar forma and how do you get to that?
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engineer
 
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Reply Wed 3 Oct, 2018 03:29 pm
@anna1918,
Polar form consists of an angle and a distance. The distance is sqrt[ 2.2^2 + 30^2] = 30.1. To get the angle, draw out the vector answer you have below. You end up 2.2 units below the x axis and 30 units above the Y axis. To find that angle, take the arc tan of (30 / -2.2)
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maxdancona
 
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Reply Wed 3 Oct, 2018 05:52 pm
@anna1918,
This is a very similar question to your displacement and velocity question. There is a reason that your teacher gave you these two questions in order. You should understand the first question before you try to understand the other.

Engineer is giving you the correct answer... but you should try to understand the concept behind it. Hopefully in class you are drawing vector diagrams (with lines and pointed arrows). Understand these diagrams is really important, or else you are just plugging numbers into arctans (which is no fun and no use to anyone).

Here is a pretty good explanation. https://www.universalclass.com/articles/math/pre-calculus/precalculus-using-polar-coordinates.htm

If you don't understand the diagrams... you should get help, hopefully you can get help from your teacher.
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