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Finding the velocity an Object Projected Vertically Upwards

 
 
Reply Thu 9 Nov, 2017 10:12 am
An Object Projected Vertically Upwards a heght of h. This moves under the gravitational force (g).If there is no energy wasted, write an equation to find the Velocity(V) of the object.
 
AngleWyrm-paused
 
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Reply Thu 9 Nov, 2017 11:15 am
@Kovindathisal,
Velocity in the context of motion is defined as distance/time; it could be miles/hour for a car, cm/year for coral growth or meters/second for a bullet.

Throw a ball straight up, hard; notice that it was moving quickly upward when it left your hand, and at some point it is moving downward back toward your hand. How fast that ball is moving upward is its velocity, which changes during the toss. Maybe 1 second after throwing the ball its still traveling quickly up, but after two seconds its barely moving upward, and three seconds after the toss its already on its way back down (negative speed upward).

How fast the ball is traveling depends on when we look at the ball. Gravity is a change in how fast things move, an acceleration. The speed of the object is its starting location + present speed + the effects of gravity after some amount of time has elapsed.

startingLocation + distanceTraveled/timeElapsed + gravityAdjustment/timeElapsed^2
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maxdancona
 
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Reply Thu 9 Nov, 2017 11:21 am
@Kovindathisal,
I was a Physics teacher, so I can give you real help (the previous poster knows nothing about Physics). I assume that your teacher has given you these two functions.

d = V0 * t + 1/2 a * t^2

Vf = V0 + a * t

In this question, the gravitational acceleration (a) is -9.8 m/s/s. I am defining up as positive for this function. Vf (the velocity when the object reaches it highest point) is 0 m/s.

I don't do people's homework for them, I will give more help if you need. You want to solve for what I am calling V0 (the starting velocity). If you take a shot at the algebra, I can tell you if you are going the right direction, or give you hints if you need them.
AngleWyrm-paused
 
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Reply Thu 9 Nov, 2017 11:30 am
@maxdancona,
startingLocation = distance/time^0
distanceTraveled/timeElapsed = distance/time^1
gravityAdjustment/timeElapsed^2 = distance/time^2

Try to understand and it will take you farther than reciting a physics book.
maxdancona
 
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Reply Thu 9 Nov, 2017 11:32 am
@AngleWyrm-paused,
I am assuming that the OP is taking a real physics class, using a real physics book getting this problem from a real physics teacher. Given the fact that this student is enrolled in a Physics class, he or she probably already knows more than you do on the subject.

Your nonsense isn't going to be helpful to this student who is working on solving real physics problems.

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